Answer:
The answer to your question is False.
Explanation:
Data
1 mole of NH₄NO₃
0.75 moles of N₂O
Percent yield = 25%
Chemical reaction
NH₄NO₃ ⇒ N₂O + 2H₂O
Process
1.- Determine the theoretical yield
1 mol NH₄NO₃ ------------- 1 mol of N₂O
2.- Calculate the percent yield
Percent yield = Actual yield / Theoretical yield x 100
-Substitution
Percent yield = 0.75 / 1 x 100
-Simplification
Percent yield = 0.75 x 100
-Result
Percent yield = 75%
Conclusion
False, the actual percent yield is 75%
Can’t tell ya bc you didn’t list the answers
Answer:
About one valence electron
Explanation:
Obviously, removing that electron gives us [Ar] (same configuration as K1+), which is a noble gas and has 8 electrons. Valence electrons are generally regarded as being 'the outermost electrons' for a given atom. Therefore, with neutral potassium, there is one valence electron
molarity of a solution means mols per liter.
First, you need to convert 23 grams on NaCl into mols. 23g divided by molar mass (58.44g/mol) which gives you .394 mols.
Now, you need to convert 500ml to L which moves the decimal three places to the left, giving you .500L of solution.
Finally, divide the mols over solution to get .787M
