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3 years ago

Select the examples of Energy tasks. Check all that apply.

Engineering

2 answers:

Arada [10]3 years ago

5 0

Answer:

B. maintaining equipment

C. performing inspections

E. analyzing information

G. designing systems

Explanation:

or 2,3,5,7

Edge 2021!

Natali5045456 [20]3 years ago

4 0

Answer:

b c e g

Explanation:

right on edge 2020

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Discuss the differences between conduction and convective heat transfer.

FrozenT [24]

Answer:

Basically there are two principal differences between the convection and conduction heat transfer

Explanation:

The conduction heat transfer is referred to the transfer between two solids due a temperature difference, while for, the convective heat transfer is referred to the transfer between a fluid (liquid or gas) and a solid. Also, they used different coefficients for its calculation.

We can include on the explanation that conduction thermal transfer is due to temperature difference, while convection thermal transfer is due to density difference.

8 0

3 years ago

In Lab 7, we worked through a program that displayed the homeless shelter occupancy over time. The same approach can be used for

Bezzdna [24]

Answer:

Explanation:

The python code to generate this is quite simple to run.

i hope you understand everything written here, you can as well try out other problems to understand better.

First to begin, we import the package;

Code:

import pandas as pd

import matplotlib.pyplot as plt

name = input('Enter name of the file: ')

op = input('Enter name of output file: ')

df = pd.read_csv(name)

df['Date'] = pd.to_datetime(df["Date"].apply(str))

plt.plot(df['Date'],df['Absent']/(df['Present']+df['Absent']+df['Released']),label="% Absent")

plt.legend(loc="upper right")

plt.xticks(rotation=20)

plt.savefig(op)

plt.show()

This should generate the data(plot) as seen in the uploaded screenshot.

thanks i hope this helps!!!

6 0

3 years ago

Reference Parameters (returning multiple values): Write a C++ function that converts standard time to military time. Inputs incl

valkas [14]

Answer:

Code is given as below:

Explanation:

#include <iostream>

using namespace std;

//function prototype declaration

void MilitaryTime(int, int, char, int &, int &);

int main()

{

//declare required variables

int SHour, SMin, MHour, MMin;

char AorP;

//promt and read the hours from the user

cout<<"Enter hours in standard time : ";

cin>>SHour;

//check the hours are valid are not

while(SHour<0 || SHour>12)

{

cout<<"Invalid hours for standard time. "

<<"Try again..."<<endl;

cout<<"Enter hours in standard time : ";

cin>>SHour;

}

//promt and read the minutes from the user

cout<<"Enter minutes in standard time : ";

cin>>SMin;

//check the minutes are valid are not

while(SMin<0 || SMin>59)

{

cout<<"Invalid minutes for standard time. "

<<"Try again..."<<endl;

cout<<"Enter minutes in standard time : ";

cin>>SMin;

}

//promt and read the am or pm from the user

cout<<"Enter standard time meridiem (a for AM p for PM): ";

cin>>AorP;

//check the meridiem is valid are not

while(!(AorP=='a' || AorP=='p' || AorP=='A' || AorP=='P'))

{

cout<<"Invalid meridiem for standard time. "

<<"Try again..."<<endl;

cout<<"Enter standard time meridiem (a for AM p for PM): ";

cin>>AorP;

}

//call function to calculate the military time

MilitaryTime(SHour, SMin, AorP, MHour, MMin);

//fill zeros and display standard time

cout.width(2);

cout.fill('0');

cout<<SHour<<":";

cout.width(2);

cout.fill('0');

cout<<SMin;

if(AorP=='a' || AorP=='A')

cout<<" am = ";

else

cout<<" pm = ";

//fill zeros and display military time

cout.width(2);

cout.fill('0');

cout<<MHour;

cout.width(2);

cout.fill('0');

cout<<MMin<<endl;

system("PAUSE");

return 0;

}

//function to calculate the military time with reference parameters

void MilitaryTime(int SHour, int SMin, char AorP, int &MHour, int &MMin)

{

//check the meredium is am or pm

//and calculate hours

if(AorP=='a' || AorP=='A')

{

if(SHour==12)

MHour = 0;

else

MHour = SHour;

}

else

MHour = SHour+12;

MMin = SMin;

5 0

3 years ago

(a) If 5 x 10^17 phosphorus atoms per cm3 are add to silicon as a substitutional impurity, determine the percentage of silicon a

Y_Kistochka [10]

Answer:

The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice = 0.001 %

The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice with boron atoms = 0.4 × $10^{-5}$ %

Explanation:

No. of phosphorus atoms = 5 × $10^{17} \ cm^{-3}$

The volume occupied by a single Si atom

$V_{si} = \frac{a^{3} }{8}$

$V_{si} = \frac{5.43^{3}(10^{-8} )^{3} }{8}$

$V_{si} =$ 2 × $10^{-23}$ $\frac{cm^{3} }{atom}$

$n_{si} = \frac{1}{V_{si} }$

$n_{si}$ = 5 × $10^{22}$ $\frac{atoms}{cm^{3} }$

$PCT = \frac{N_p}{N_{si}} 100$

Put the values in above equation we get

$PCT = \frac{5 (10^{17} )}{5 (10^{22}) } 100$

PCT = $10^{-3} = 0.001$ %

These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.

(b).

No. of boron atoms = 2 × $10^{15} \ cm^{-3}$

The volume occupied by a single Si atom

$V_{si} = \frac{a^{3} }{8}$

$V_{si} = \frac{5.43^{3}(10^{-8} )^{3} }{8}$

$V_{si} =$ 2 × $10^{-23}$ $\frac{cm^{3} }{atom}$

$n_{si} = \frac{1}{V_{si} }$

$n_{si}$ = 5 × $10^{22}$ $\frac{atoms}{cm^{3} }$

$PCT = \frac{N_p}{N_{si}} 100$

Put the values in above equation we get

$PCT = \frac{2 (10^{15} )}{5 (10^{22}) } 100$

PCT = 0.4 × $10^{-5}$ %

These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.

7 0

3 years ago

1. Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3 is compressed slowly in an isothermal process to a final pressure

Sauron [17]

Answer:

Workdone during the process = 130kJ

Explanation:

Workdone by an expanding gas which is also called pressure-volume work, is defined as the pressure exerted by the gas molecules on the walls of the containing vessel. If work done by an expanding gas is the energy transferred to its surroundings i.e If volume increases, workdone is negative(loses energy).

In an isothermal process(constant Temperature of 300K, we use boyles law:

P1V1 = P2V2

V2 = (150 * 0.2)/800

= 0.0375 m3

W = -P(V2 - V1)

= 800*(0.0375 - 0.200)

= 130kJ

7 0

3 years ago