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Montano1993 [528]
3 years ago
13

Problems in Context Which separation method is operating in each of the following procedures? (a) Pouring a mixture of cooked pa

sta and boiling water into a colander (b) Removing colored impurities from raw sugar to make refined sugar
Chemistry
1 answer:
Serga [27]3 years ago
7 0

Answer:

( a ) Filtration

( b ) sugar refining .

Explanation:

( a ) Filtration

By the process of filtration pasta from water can be removed , as pasta is not soluble in water , hence , by filtration , the solid pasta will remain in the filtration funnel , and the water will flow down , thereby , removing pasta from the water .

( b ) sugar refining

The raw sugar can be purified from the process of sugar refining .

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Which statements accurately compare the environmental impact of acquiring natural gas and acquiring oil? Select the two correct
solmaris [256]

Answer:

Both involve drilling into the earth and can cause environmental degradation.

Explanation:

6 0
3 years ago
Read 2 more answers
What is the answer to question 7, NH4C2H3O2
Montano1993 [528]
I think it got deleted but the answer is Ammonium acetate maybe this is why it got deleted 10-9=1
3 0
3 years ago
An air stream enters a variable area channel at a velocity of 30 m/s with a pressure of 120 kPa and a temperature of 10°C. At a
nekit [7.7K]

Answer:

P₂= 74 kPa under constant density and ρ₂ = 1.06 kg/m³ (-38.6% of error compared with incompresible assumption) . Thus Bernoulli’s equation should not be applied

Explanation:

Assuming ideal gas behaviour of air , then

P*V= n*R*T = m / M * R *T

since

ρ= m/V = P*M /( R *T)

where

n= moles , V= volume , m= mass

ρ= density

P= pressure = 120 kPa= 120000 Pa

M= molecular weight of air = 0.21*32+0.79*28= 28.24 gr/mol = 0.02824 kg/mol

T= absolute temperature = 10°C + 273 = 283 K

R= ideal gas constant = 8.314 J/mol K

solving for ρ

ρ=  P*M /( R *T) = 120000 Pa*0.02824 kg/mol/(8.314 J/mol K*283 K) = 1.47 kg/m³

then from Bernoulli's equation

P₁ + ρ*v₁²/2 = P₂ + ρ*v₂²/2

where 1 denotes inlet and 2 denotes other point , p = pressure and v= velocity . Then solving for p₂

P₁ + ρ*v₁²/2 = P₂ +ρ*P₂²/2

P₂=  P₁ +ρ*v₁²/2 - ρ*v₂²/2  = P₁ +ρ/2*(v₁² - v₂²)

replacing values

P₂= P₁ +ρ/2*(v₁² - v₂²) = 120000 Pa + 1.47 kg/m³/2*[(30 m/s)²-(250 m/s)²] = 74724 Pa = 74 kPa

P₂= 74 kPa

then if the temperature remains constant

ρ₁= P₁*M /( R *T) and ρ₂= P₂*M /( R *T)

dividing both equations

ρ₂/ρ₁ = P₂/ P₁

ρ₂ = (P₂/ P₁)*ρ₁

then from Bernoulli's equation

P₁ + ρ₁*v₁²/2 = P₂ + ρ₂*v₂²/2

P₂ = P₁ + ρ₁*v₁²/2 - ρ₂*v₂²/2

therefore

ρ₂ = (P₂/ P₁)*ρ₁ = (P₁ + ρ₁*v₁²/2 - ρ₂*v₂²/2 ) /P₁ *ρ₁

P₁ * ρ₂  = P₁ *ρ₁  + ρ₁²*v₁²/2 - ρ₂*ρ₁ * v₂²/2

P₁ * ρ₂ + ρ₂*ρ₁ * v₂²/2  = P₁ *ρ₁  + ρ₁²*v₁²/2

ρ₂* (P₁ + ρ₁ * v₂²/2) = P₁ *ρ₁  + ρ₁²*v₁²/2

ρ₂ = (P₁ *ρ₁  + ρ₁²*v₁²/2)/(P₁ + ρ₁ * v₂²/2) =  (P₁ + ρ₁*v₁²/2)/(P₁/ρ₁ + v₂²/2)

replacing values

ρ₂ = ( 120000 Pa + 1.47 kg/m³/2*(30 m/s)²)/(120000 Pa/1.47 kg/m³+1/2*(250 m/s)²)

ρ₂ = 1.06 kg/m³

the error of assuming constant ρ would be

e = (ρ₂ - ρ)/ρ₂=  1- ρ/ρ₂= 1- 1.47 kg/m³/1.06 kg/m³ = -0.386 (-38.6%)

thus Bernoulli’s equation should not be applied

8 0
3 years ago
What is the empirical formula for a compound that contains 38.77% Cl and 61.23% O?
Leno4ka [110]
W(Cl)=0.3877
w(O)=0.6123
M(Cl)=35.5 g/mol
M(O)=16.0 g/mol

ClₐOₓ
M(ClₐOₓ)=35.5a+16.0x

w(Cl)=35.5a/(35.5a+16.0x)
w(O)=16.0x/(35.5a+16.0x)

solve a system of two equations with two unknowns
35.5a/(35.5a+16.0x)=0.3877
16.0x/(35.5a+16.0x)=0.6123

a=2
x=7

Cl₂O₇ is the empirical formula
3 0
3 years ago
Two 25.0-mL aqueous solutions, labeled A and B, contain the ions indicated:
asambeis [7]

The additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL

The moles of HCl which is required to reach the equivalence point can be calculated in the way as follows.

Moles of HCl can be calculated as

Moles of HCl = 0.004 moles of Ca (OH) 2 × 2 moles of HCl / 1 moles of Ca (OH) 2

= 0.008 moles of HCl

The volume of HCl which is required to reach the equivalence point can be calculated in the way given as follows.

Volume of HCl required= 0.008 moles of HCl × 1 L / 0.24 moles of HCl × 1 ml / 10 -³ L

= 33.33 ml

The additional volume of HCl calculated as

Additional volume = required volume – actual volume

= 33.33 mL – 25 mL

= 8 . 33 mL

Thus, we calculated that the additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL.

learn more about equivalence point:

brainly.com/question/19997690

#SPJ4

4 0
10 months ago
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