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Montano1993 [528]
3 years ago
13

Problems in Context Which separation method is operating in each of the following procedures? (a) Pouring a mixture of cooked pa

sta and boiling water into a colander (b) Removing colored impurities from raw sugar to make refined sugar
Chemistry
1 answer:
Serga [27]3 years ago
7 0

Answer:

( a ) Filtration

( b ) sugar refining .

Explanation:

( a ) Filtration

By the process of filtration pasta from water can be removed , as pasta is not soluble in water , hence , by filtration , the solid pasta will remain in the filtration funnel , and the water will flow down , thereby , removing pasta from the water .

( b ) sugar refining

The raw sugar can be purified from the process of sugar refining .

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A cylinder of oxygen gas has a volume of 10.0 liters at 7.66 atm and 27.0oC. The cylinder is heated until the pressure is 428 kP
iris [78.8K]

Answer:

Explanation:

428 x 10³ Pa = 4.28 x 10⁵ Pa = 4.28 atm

We shall use the gas equation

P₁V₁ / T₁ = P₂V₂ / T₂

7.66  x 10 / ( 273 + 27 ) = 4.28 x 30 / T₂

.255 = 128.4 / T₂

T₂ = 503.53

= 503.53 - 273 = 230.53⁰C .

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3 years ago
lighting a match results in light and heat since energy was not created by the match what transformation took place
Feliz [49]
I think if was chemical energy hope I helped
3 0
3 years ago
If kb for nx3 is 1.5×10−6, what is the poh of a 0.175 m aqueous solution of nx3?
Charra [1.4K]
Answer is: pOH = 3,29.
Kb(NH₃) = 1,5·10⁻⁶.
c(NH₃) = 0,175M.
pOH = ?
Chemical reaction: NH₃ + H₂O ⇄ NH₄⁺ + OH⁻.
Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).
c(NH₄⁺) = c(OH⁻) = x.
x² = Kb · c(NH₃) 
x² = 1,5·10⁻⁶ · 0,175 = 2,625 ·10⁻⁷.
x = c(OH⁻) = √2,625 ·10⁻⁷ = 5,12 · 10⁻⁴.
pOH = -log(c(OH⁻)) = 3,29.

3 0
3 years ago
What is the symbol of gold ​
Soloha48 [4]

Explanation:

Tha Symbol of gold is Au.

4 0
3 years ago
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Which of the following statements about the Diels-Alder reaction are TRUE?
andreev551 [17]

Answer:

A.It is a reaction involving pi-electrons.

D.It is *not* a reaction favored by entropy considerations.

Explanation:

The Diels-Alder reaction is a [4+2]- cycloadition that involoves pi-electrons (4 from the diene and 2 from the dienophile).

The reaction is favored by the formation of new sigma bond, since they are more stable than pi-bonds. This reaction is not favored by entropy because there are 2 reactants and one product and the order increases.

The reaction happens in one step.

6 0
3 years ago
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