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Wittaler [7]
3 years ago
9

Name two solid liquid and gaseous element at the normal temperature and normal pressure​

Chemistry
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

Solid: calcium and potassium

Liquid: mercury and bromine

Gaseous: oxygen and fluorine

Explanation:

Matter exists in three different states namely: solid, gaseous and liquid. Elements that are found in nature are classified as matter. Since, these elements are grouped as matter, they can either be found as either solids, liquids or gases at normal temperature and pressure.

At normal temperature (20°C or 293K) and pressure (1 atm), the following elements are found to exists in the respective state of matter:

Solid: Calcium (Ca) and potassium (K)

Liquid: Mercury (Hg) and bromine (Br)

Gaseous: Oxygen (O) and fluorine (F)

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If the amount of gas and volume are constant and you double the temperature of the gas, pressure halves
Lapatulllka [165]

Explanation:

if we fix the temperature, we are just left with PV = constant for the gas law. So, in this situation, if the volume is doubled, the pressure must go down by one-half. And vice-versa. The simplest illustration of this would be a cylinder with a plunger on one end: if you push the plunger in so that the volume of the cylinder is halved and the temperature remains constant, then the pressure will double.

7 0
3 years ago
Identify each type of bond:
zloy xaker [14]

Answer:

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Hope it helped

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6 0
3 years ago
A pea plant has two dominant alleles for plant height – tall. We say that this plant is?:
Irina-Kira [14]
I think the answer is codominant??
3 0
2 years ago
The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br_2(g

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}

Given: -\frac{d[HBr]}{dt}]=0.301

Putting in the values we get:

\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}

+\frac{1d[Br_2]}{dt}=0.151

Thus the rate of appearance of Br_2 is 0.151

8 0
3 years ago
PLEASE HELP!!!!!
Free_Kalibri [48]
Umm I think it might be a b c in order?
4 0
2 years ago
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