Name two solid liquid and gaseous element at the normal temperature and normal pressure

Chemistry

1 answer:

liubo4ka [24]3 years ago

7 0

Answer:

Solid: calcium and potassium

Liquid: mercury and bromine

Gaseous: oxygen and fluorine

Explanation:

Matter exists in three different states namely: solid, gaseous and liquid. Elements that are found in nature are classified as matter. Since, these elements are grouped as matter, they can either be found as either solids, liquids or gases at normal temperature and pressure.

At normal temperature (20°C or 293K) and pressure (1 atm), the following elements are found to exists in the respective state of matter:

Solid: Calcium (Ca) and potassium (K)

Liquid: Mercury (Hg) and bromine (Br)

Gaseous: Oxygen (O) and fluorine (F)

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For the reaction COCl2(g)⇌CO(g)+Cl2(g), K= 2.19×10−10 at 373 K

vladimir1956 [14]

Answer:

D) The equilibrium lies far to the left

Explanation:

According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:

K = $\frac{[CO][Cl_{2}]}{[COCl_{2}]}$ = 2.19×10^{-10}

([X] means = concentration of X)

This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.

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The highest pressure ever produced in a laboratory setting was about 2.0 x 10 6 atm. If we have a

tigry1 [53]

Answer:

Volume = 72.7272

Explanation:

if only pressure and volume change, then we can do some simple math to find the answer.

2 x 10 ^ 6 times 1 x 10 ^-5 = 20

pressure and volume must equal 20

20 = 0.275 x volume

20 / 0.275 = new volume