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Wittaler [7]
3 years ago
9

Name two solid liquid and gaseous element at the normal temperature and normal pressure​

Chemistry
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

Solid: calcium and potassium

Liquid: mercury and bromine

Gaseous: oxygen and fluorine

Explanation:

Matter exists in three different states namely: solid, gaseous and liquid. Elements that are found in nature are classified as matter. Since, these elements are grouped as matter, they can either be found as either solids, liquids or gases at normal temperature and pressure.

At normal temperature (20°C or 293K) and pressure (1 atm), the following elements are found to exists in the respective state of matter:

Solid: Calcium (Ca) and potassium (K)

Liquid: Mercury (Hg) and bromine (Br)

Gaseous: Oxygen (O) and fluorine (F)

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A man weighs 185 lb. What is his mass in grams?<br> Please show work.<br> Thank you
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Answer:

83914.52 grams

Explanation:

Given that,

Weight of a man is 185 lb

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185 lb = (453.592 × 185) grams

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What is the pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at
lyudmila [28]

The pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at 145 kPa and 176°C is 1.195 atm.

<h3>What is ideal gas equation?</h3>

Ideal gas equation of any gas will be represented as:
PV = nRT, where

P = pressure

V = volume

n = moles

R = universal gas constant

T = temperature

First we calculate the moles of gas, when the volume of gas 875 ml at

145 kPa and 176°C as:

n = (1.431atm)(0.875L) / (0.082L.atm/K.mol)(449.15K)

n = 1.252 / 36.83 = 0.033 moles

Now we measure the pressure of 0.033 moles of gas of 1.27 L of a gas at 288°C as:

P = (0.033mol)(0.082L.atm/K.mol)(561K) / (1.27L) = 1.195 atm

Hence required pressure of gas is 1.195 atm.

To know more about ideal gas equation, visit the below link:
brainly.com/question/555495

#SPJ1

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