Answer:
57.885.8 kg weight of the container
Explanation:
The volume of the balloon * density of water = buoyant force of balloon
volume of a sphere = 4/3 pi r^3
= 4/3 pi * (1.5)^3 = 14.14 m^3 <===balloon volume
Now, find the buoyant force on the container ALONE ....
5.8 * 2.6 * 2.8 * 1027 = 43 364 kg <===== buoyant force
Now add the buoyant force of the balloon to find the weight
43 364 + 14.14 * 1027 = 57885.8 kg
Answer:Interference
Explanation:destructive interference
Answer:
V0=27.4 m/s; t=0.8 s
Explanation:
Final position y=37.0 m, time = 2.3 s; Initial position is set to be zero. We calculate the initial speed with the kinematics equation:
We solve for initial speed
Now, using the same expression we estimated time to first reach 18.5 m :
Second order equation with solutions
t1=0.8 s and t2=4.8 s
The first time corresponds to the first reach.
Mechanical waves are the answer
Answer:
I = 1.093 x 10⁻⁴ kg.m²
Here, all the other data, namely, the height of the can, length of the inclined plane, angle of inclination, time to reach the bottom, are unnecessary.
Explanation:
The can which is filled with the soup can be modelled as a solid cylinder. The moment of inertia of this solid cylinder about its axis of rotation can be given by the following formula:
where,
I = moment of inertia of can = ?
m = mass of can with soup = 215 g = 0.215 kg
r = radius of can = diameter/2 = 6.38 cm/2 = 3.19 cm = 0.0319 m
Therefore,
<u>I = 1.093 x 10⁻⁴ kg.m²</u>
<u>Here, all the other data, namely, the height of the can, length of the inclined plane, angle of inclination, time to reach the bottom, are unnecessary.</u>