Answer:
The generic equation for a combustion reaction is AB + O2 à AO + BO
Explanation:
1. NaCl
2. CaO
3. KOH
4. MgS
5. CuCO3
6. Al2O3
7. Fe2O3
8. Na2CO3
9. AlHO3
10. (NH4)3N
11. Zn3N2
12. MgCO3
All numbers are subscripts.
Answer:
H₂O.
Explanation:
- It is clear from the balanced equation:
<em>CH₄ + 2H₂O → CO₂ + 4H₂.</em>
that 1.0 mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.
- To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:
<em>n = mass/molar mass</em>
<em></em>
no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.
no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.
- <em>from the balanced reaction, 1.0 mole of CH₄ reacts with 2.0 moles of H₂O.</em>
So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.
<u><em>So, the limiting reactant is H₂O.</em></u>
Sufficient energy upon collision of particles and correct orientation of particles
