Question

Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

Answer 1

The question is incomplete, the complete question is:

Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

(a): Calculate the grams of $N_2$ in 10.58 L of nitrogen gas

(b): Calculate the grams of $N_2$ in $5.03\times 10^{20}$ moles of nitrogen gas

(c): Calculate the moles of $N_2$ molecules in 3.94 grams of nitrogen gas

(d): Calculate the moles of $N_2$ molecules in 4.73 L of nitrogen gas

Answer: The correct options are (b) and (c).

Explanation:

We are given:

Molar mass of $N_2$ = 28.02 g/mol

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

At STP conditions:

1 mole of gas occupies 22.4 L of volume

For the given options:

(a): Volume is given and to calculate the mass of $N_2$, we need to use both the conversion factors above.

The equation formed will be:

Mass of $N_2$ = $\frac{1mol}{22.4L}\times 10.58L\times 28.02 g/mol$

(b): Moles are given and to calculate the mass of $N_2$, we need only the first conversion factor.

The equation formed will be:

Mass of $N_2$ = $(5.03\times 10^{20}mol)\times 28.02g/mol$

(c): Mass is given and to calculate the moles of $N_2$ molecules, we need only the first conversion factor.

The equation formed will be:

Moles of $N_2$ molecules = $\frac{3.94 g}{28.02g/mol}$

(d): Volume is given and to calculate the moles of $N_2$ molecules, we need only the second conversion factor.

The equation formed will be:

Moles of $N_2$ molecules = $\frac{1mol}{22.4L}\times 4.73L$

Hence, the correct option is (b) and (c)