Answer:
Tigers and lions able to mate to produce cubs,but those cubs would not be able to go on to produce any off spring because their sex chromosomes do not match.
Explanation:
- Tigers and lions mate to produce ligers and tilons but they do not produce viable sperms or egg.
- In an organism there are two copies of chromosomes present in the somatic cells.
- But in case of sex cells they receive each set from mother and father. which they duplicate and divide during formation of gametes via meiosis.
- in such case if the sets are recieved from two different species then after pairing a mismatch will occur in the gene loci.For example, a eye colour gene may correspond to a paw length gene.
- Thus the gametes when produced will not be viable.
Answer:
See the answer below
Explanation:
<em>First, it should be understood that an endothermic reaction is one that absorbs energy in the form of heat from the surrounding.</em> The products of endothermic reactions usually have higher energy than their reactants. Hence, the ΔH° which is referred to as the enthalpy change is usually positive.
<u>Forgetting to cover the coffee-cup calorimeter means some of the heat energy absorbed by the reactants would be exchanged back to the surroundings - a loss.</u> It also means that the enthalpy change would be smaller compared to if the cup had been covered because some of the heat has been lost to the surrounding.
This is a basic orbital diagram for carbon
Answer:
The whole molecule is polar because Sulfur has lone pairs but Carbon doesn't. Lone pairs count more toward polarity, shifting dipole toward S.
Explanation:
Even though carbon and sulfur have identical values of electronegativities, the molecule, 
is polar because of the presence of the lone pairs on the sulfur atom.
The C-S bond is not polar because the both the atoms have electronegatiivty. <u>But S has lone pairs which can attract the bond pairs of the bond between the S and H and thus acquires slightly negative charge and H acquires slightly positive charge.</u>
B <span>Divide the chemical equation into two half-reaction equations, identifying which half-reaction is oxidation and which is reduction
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