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3 years ago

PLEASE ANSWER ASAP

Chemistry

1 answer:

kodGreya [7K]3 years ago

7 0

Answer:It is C i got it correct

Explanation:

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The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?

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<u>Answer:</u> The molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

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s 2s

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$K_{sp}=[Pb^{2+}][I^-]^2$

We are given:

$K_{sp}=7.9\times 10^{-9}$

Putting values in above equation, we get:

$7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L$

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Answer: $ClF$ will have a greater partial charge.

Explanation:

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Thus as $ClF$ will have greater partial charge.

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