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3 years ago

Which of the following is not a racquet sport?

Chemistry

2 answers:

Yanka [14]3 years ago

8 0

The answer is b.volleyball

Mekhanik [1.2K]3 years ago

6 0

Answer:

Volleyball

Explanation:

A P E X :)

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The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21 x 10-8 cm. What is this distance in inche

Sergio [31]

Answer:

$d=4.75\times 10^{-9}\ \text{inches}$

Explanation:

Given that,

The distance between the centers of the two oxygen atoms in an oxygen molecule is $1.21\times 10^{-8}\ cm$ .

We need to convert this distance in inches.

We know that,

1 cm = 0.393 inches

We can solve it as follows :

$1.21\times 10^{-8}\ cm=0.393\times 1.21\times 10^{-8}\\\\=4.75\times 10^{-9}\ \text{inches}$

So, the distance between the centers of the two oxygen atoms is $4.75\times 10^{-9}\ \text{inches}$ .

5 0

2 years ago

How many moles of H2SO4 are present in 0.500 L of a 0.150 M H2SO4 solution?

bonufazy [111]

Answer: 0.075

Explanation:

(concentration in molarity)(volume in liter) = answer

0.15 mol/L *0.500L = 0.075 mol

3 0

3 years ago

What is the difference in mesomeric and electromeric effect

Leya [2.2K]

Cause their are both have difference s

8 0

3 years ago

Sodium carbonate reacts with silver nitrate according to the following balanced equation: Na2CO3 (s) + 2 AgNO3 (aq) → Ag2CO3 (s)

klemol [59]

Answer:

a) 2.01 g

Explanation:

Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃

First we convert 0.0302 mol AgNO₃ to Na₂CO₃ moles, in order to calculate how many Na₂CO₃ moles reacted:

0.0302 mol AgNO₃ * $\frac{1molNa_2CO_3}{2molAgNO_3}$ = 0.0151 mol Na₂CO₃

So the remaining Na₂CO₃ moles are:

0.0340 - 0.0151 = 0.0189 moles Na₂CO₃

Finally we convert Na₂CO₃ moles into grams, using its molar mass:

0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃

The closest answer is option a).

8 0

3 years ago

(d) carbon monoxide

Irina18 [472]

Answer:

D. carbon monoxide

Hope this helps :)

6 0

2 years ago