Answer:
The answer to your question is Volume = 0.12 L
Explanation:
- Data
Pressure 1 = 1 atm
Volume 1 = 1.82 L
Pressure 2 = 15 atm
Volume 2 = ?
Temperature = constant
- Formula
- To solve this problem use the Boyle's law
P1V1 = P2V2
- Solve for V2
V2 = P1V1 / P2
- Substitution
V2 = (1)(1.82) / 15
- Simplification
V2 = 1.82 / 15
- Result
V2 = 0.12 L
<h2>Solutions:</h2>
<u>Case a:</u> Finding pH for [H⁺] = 1.75 × 10⁻⁵ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [1.75 x 10⁻⁵]
pH = 4.75
<u>Case b:</u> Finding pH for [H⁺] = 6.50 × 10⁻¹⁰ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [6.50 × 10⁻¹⁰]
pH = 9.18
<u>Case c:</u> Finding pH for [H⁺] = 1.0 × 10⁻⁴ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [1.0 × 10⁻⁴]
pH = 4
<u>Case d:</u> Finding pH for [H⁺] = 1.50 × 10⁻⁵ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [1.50 × 10⁻⁵]
pH = 4.82
Explanation:
The boiling point of petrol is 483K and that of water in 373K. Since the difference between the boiling point temperatures is high, we can use the method of distillation as explained above to obtain petrol and water from the liquid mixture. Therefore, the correct answer is option (A).
Thermal energy because you need to boil the water and thermal energy is needed to create the heat.....