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natta225 [31]
3 years ago
15

When placed in a 100-mL square box, a substance has a spherical shape and has a volume of 50 mL. When placed in a 100-mL circula

r tube, that same substance has a spherical shape and a 50-mL volume. In what phase or state was the substance?

Chemistry
2 answers:
Nady [450]3 years ago
8 0
The given substance is SOLID. Solids have definite shape and definite volume. By the term definite we mean that wherever it may be placed both shape and volume remain the same. From the given above, the substance has a definite shape of sphere and definite volume of 50 mL. 
forsale [732]3 years ago
4 0
When placed in a 100-mL square box, a substance has a spherical shape and has a volume of 50 mL. When placed in a 100-mL circular tube, that samesubstance has a spherical shape and a 50-mL volume.The substance was in Solid State.

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HELP ASAP!!
Ksju [112]
109/8.56=12.7
50+12.7
V=62.7

Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer

4 0
3 years ago
Read 2 more answers
Example of transforming from electric energy to chemical energy<br> please!!!
Alik [6]

Answer:

Charging a chemical battery is a simple example of converting electricital energy to chemical energy.

Explanation:

4 0
3 years ago
identify 2 changes of state that require energy to be used, and 2 changes of state that require the release of energy
solniwko [45]

Answer:

used=Evaporation and sublimation

released=condensation and freezing

Explanation:

8 0
3 years ago
One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO
zhenek [66]
Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
 2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s)  and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
                                                                                     = 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
                                                         = 1000 x 10³ g / 226 g mol⁻¹
                                                         = 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x \frac{3}{2}
                                                     = 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
                                        = 703540.02 g
                                        = 703.540 kg

Hence, the theoretical yield of Na₂CO₃ =  703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
                            = 92.34%
7 0
3 years ago
1. The electron configuration below represents the ground state of an atom.
Natalka [10]

Answer:

{S}^{16}

group 16 period 2 of the periodic table

note: that is not the electronic configuration, that is the Bohr model.

4 0
2 years ago
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