2 years ago

HELP FAST

Physics

1 answer:

katen-ka-za [31]2 years ago

3 0

Answer:

C. 2 and 4

Explanation:

my teacher went over it and the answer was that

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The process of wind blowing sand from one location to another is called

lesya [120]

Answer:

weathering

Explanation:

3 0

3 years ago

Read 2 more answers

Hii! help asap. i’ll give brainliest thanks!

o-na [289]

I believe it’s the mass of the box but I don’t no if I’m right

Hope this helped

5 0

3 years ago

A string attached to an airborne kite was maintained at an angle of 40.0 with the ground. if 120m of string was reeled in to ret

AleksAgata [21]

The hypotenuse is measured at 120 meters of string, and you need to solve for the leg of the triangle that is horizontal. The degree is 40, so use trigonometry to figure it out.
Cosin (40) is equal to around .766
Adjacent/Hypotenuse
x/120 = cos40
Answer: 91.92533.
If you use 3 significant figures it should be 91.9 meters.

5 0

3 years ago

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 34.5

Inessa05 [86]

Answer:

the acceleration of the airplane is 5.06 x 10⁻³ m/s²

Explanation:

Given;

initial velocity of the airplane. u = 34.5 m/s

distance traveled by the airplane, s = 46,100 m

final velocity of the airplane, v = 40.7 m/s

The acceleration of the airplane is calculated from the following kinematic equation;

v² = u² + 2as

$2as= v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(40.7)^2 -(34.5)^2}{2 \times 46,100} \\\\a = 5.06 \ \times \ 10^{-3} \ m/s^2$

Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²

5 0

3 years ago

A woman rides a carnival Ferris wheel at radius 20 m, completing 6.0 turns about its horizontal axis every minute. What are (a)

natta225 [31]

Answer:

Explanation:

Given

radius of ferris wheel is 20 m

It completes 6 turns in 1 min

i.e. 1 turn in 10 sec

Therefore its angular velocity is $\omega =\frac{2\pi }{10} rad/s$

(a)Period of motion is 10 s

Magnitude of centripetal acceleration is $\omega ^2r$

$=\left ( \frac{\pi }{5}\right )^2\times 20=7.89 m/s^2$

(b)Highest point will be 40 m

7 0

3 years ago