Answer: acceleration is equal to the change in velocity per unit time in seconds.
a= ∆v / t = vf - vi / t
Explanation: change in velocity or ∆v can be expressed as (vf - vi)
If a coin is dropped at a relatively low altitude, it's acceleration remains constant. However, if the coin is dropped at a very high altitude, air resistance will have a significant effect. The initial acceleration of the coin will be the greatest. As it falls down, air resistance will counteract the weight of the coin. So, the acceleration will decrease. Although the acceleration decreases, the coin still accelerates, that is why it falls faster. When the air resistance fully counters the weight of the coin, the acceleration will become zero and the coin will fall at a constant speed (terminal velocity). So, the answer should be, The acceleration decreases until it reaches 0. The closest answer is.
a. The acceleration decreases.
Answer:
s is distance so it's dimensions become L.
Nd other side we have ut+1\2at^2.
as 1\2 is a constant it will have dimensions and apply the dimensions to other quantities.
on solving u will get L there also i,e ur LHS = RHS.
thus the equation is dimensionally consistent.
Explanation:
Answer:
6 V
Explanation:
We can solve the problem by using Ohm's law:
where
V is the voltage in the circuit
R is the resistance
I is the current
In this problem, we know the current, 
, and the resistance, 
, therefore we can find the voltage in the circuit:
