Answer:
In CO, the oxidation number of C is (+2), and that of O is (-2).
In H_2H2 , the oxidation number of H is (0).
In CH_3OHCH3OH , the oxidation number of C is (-2), that of O is (-2) and that of H is (+1).
Explanation :
Oxidation number : It is also called oxidation state. It is a number assigned to an element in a chemical compound that represent the number of electrons gained or lost by an element in a compound.
Answer:
The work done by the gas is 117,300 Joules.
Explanation:
Pressure applied on the gas , P= 102.0 kPa = 102000 Pa ( 1kPa = 1000 Pa
Change in volume of the gas ,ΔV= 
Here the work is done by system so, the value of work done will be negative.


The work done by the gas is 117,300 Joules.
Answer:
physical - arrangement of molecules changes
chemical - identity changes
Explanation:
Methylbut-2-ene undergoes asymmetric electrophilic addition with hydrogen bromide to produce two products:
, 2-bromo-<em>2</em>-methylbutane;
, 2-bromo-<em>1</em>-methylbutane.
It is expected that
would end up being the dominant product.
Explanation
Molecules of methylbut-2-ene contains regions of high electron density at the pi-bonds. Those bonds would attract hydrogen atoms with a partial positive charge in polar hydrogen bromide molecules and could occasionally induce heterolytic fission of the hydrogen-bromide bond to produce positively-charged hydrogen ions
and negatively-charged bromide ions
.

The positively-charged hydrogen ion would then attack the methylbut-2-ene to attach itself to one of the two double-bond-forming carbon atoms. It would break the pi bond (but not the sigma bond) to produce a carbo<em>cation</em> with the positive charge centered on the carbon atom on the other end of the used-to-be double bond. The presence of the methyl group introduces asymmetry to the molecule, such that the two possible carbocation configurations are structurally distinct:
;
.
The carbocations are of different stabilities. Electrons in carbon-carbon bonds connected to the positively-charged carbon atom shift toward the electron-deficient atom and help increase the structural stability of the molecule. The electron-deficient carbon atom in the first carbocation intermediate shown in the list has <em>three</em> carbon-carbon single bonds after the addition of the proton
as opposed to <em>two</em> as in the second carbocation. The first carbocation- a "tertiary" carbocation- would thus be more stable, takes less energy to produce, and has a higher chance of appearance than its secondary counterpart. The polar solvent dichloromethane would further contribute to the stability of the carbocations through dipole-dipole interactions.
Both carbocations would then combine with bromide ions to produce a neutral halocarbon.
The position of bromine ions in the resultant halocarbon would be dependent on the center of the positive charge in the carbocation. One would thus expect 2-bromo-<em>2</em>-methylbutane, stemming from the first carbocation which has the greatest abundance in the solution among the two, to be the dominant product of the overall reaction.
Answer: Iconic
Explanation:Ionic bonds are formed through the exchange of valence electrons between atoms, typically a metal and a nonmetal.