Empirical formula for S3O9

Chemistry

1 answer:

Vsevolod [243]3 years ago

7 0

Answer:

* The empirical formula of a compound shows the ratio of elements present in a compound

* The molecular formula of a compound shows how many atoms of each element are present in a molecule of a compound.

Example: the compound butene has a molecular formula of C4H8. The empirical formula

of butene is CH2 because there is a 1:2 ratio of carbon atoms to hydrogen atoms.

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Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.

Sergeeva-Olga [200]

Blood.

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Salad dressing.

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4 0

3 years ago

Read 2 more answers

Which of the following substances (with specific heat capacity provided) would show the greatest temperature change upon absorbi

JulijaS [17]

Answer:

Pb is the substance that experiments the greatest temperature change.

Explanation:

The specific heat capacity refers to the amount of heat energy required to raise in 1 degree the temperature of 1 gram of substance. The highest the heat capacity, the more energy it would be required. These variables are related through the equation:

Q = c . m . ΔT

where,

Q is the amount of heat energy provided (J)

c is the specific heat capacity (J/g.°C)

m is the mass of the substance

ΔT is the change in temperature

Since the question is about the change in temperature, we can rearrange the equation like this:

$\Delta T = \frac{Q}{c.m}$

All the substances in the options have the same mass (m=10.0g) and absorb the same amount of heat (Q=100.0J), so the change in temperature depends only on the specific heat capacity. We can see in the last equation that they are inversely proportional; the lower c, the greater ΔT. Since we are looking for the greatest temperature change, It must be the one with the lowest c, namely, Pb with c = 0.128 J/g°C. This makes sense because Pb is a metal and therefore a good conductor of heat.

Its change in temperature is:

$\Delta T = \frac{q}{c.m} = \frac{100.0 J}{0.128 J/g.C . 10.0g } = 78.1$