All categories

3 years ago

How independent are we on technology?

2 answers:

6 0

Technology makes us feel more alone because we are more dependent on social media connections than real life connections. Simply put, technology-independent architecture means not being biased towards any particular platform or software language.

Alenkinab [10]3 years ago

4 0

Answer:

you can check out any time you like. But you don't, do you? There's one area where technology has surely encouraged a truer and more heartening personal freedom. According to Gallup, a record 42 percent of Americans now identify as politically independent.

You might be interested in

Need help on this please

marin [14]

The answer is D, the amount of energy stays the same.

3 0

3 years ago

In preparation for an electrophoresis procedure, enzymes are added to DNA in order to

lapo4ka [179]

It is 2.) Cut the DNA into fragments

3 0

3 years ago

Starting with a new moon, name the phases the moon will pass through before the next new moon.

ipn [44]

Hope this helps! Please mark as brainliest!

8 0

2 years ago

A long solenoid with 1.65 103 turns per meter and radius 2.00 cm carries an oscillating current I = 6.00 sin 90πt, where I is in

Leno4ka [110]

Answer:

The electric field is $35\cos(90\pi t)\ mV/m$

Explanation:

Given that,

Radius = 2.00 cm

Number of turns per unit length $n= 1.65\times10^{3}$

Current $I = 6.00\sin 90\pi t$

We need to calculate the induced emf

$\epsilon =\mu_{0}nA\dfrac{dI}{dt}$

Where, n = number of turns per unit length

A = area of cross section

$\dfrac{dI}{dt}$ =rate of current

Formula of electric field is defined as,

$E=\dfrac{\epsilon}{2\pi r}$

Where, r = radius

Put the value of emf in equation (I)

$E=\dfrac{\mu_{0}nA\dfrac{dI}{dt}}{2\pi r}$ ....(II)

We need to calculate the rate of current

$I=6.00\sin 90\pi t$ ....(III)

On differentiating equation (III)

$\dfrac{dI}{dt}=90\pi\times6.00\cos(90\pi t)$

Now, put the value of rate of current in equation (II)

$E=\dfrac{4\pi\times10^{-7}\times1.65\times10^{3}\times\pi\times(2.00\times10^{-2})^2\times90\pi\times6.00\cos(90\pi t)}{2\pi\times 2.00\times10^{-2}}$