The answer is A. Polarized in a vertical plane
If positioned correctly, a polarized lenses can block all reflected light from horizontal surface such as road
your answer is C.Play all the songs in alphabetical order.
hope that helps !!!
Answer:
calar quantity, length of path. displacement: vector quanity, "as the crow flies" difference between start and finish regardless of path taken. Term.
Explanation:
An electromagnet is a type of magnet in which the magnetic field is produced using the current. The simplest form of an electromagnet is a wire wrapped around in a coil.
The strength of magnetic field of such magnet is given with this equation:

Where N is the number of loops in the coil, I is the strength of the current flowing through the coil, L is the length of the coil, and

is <span>permeability of the electromagnet core material.
From this equation, we can see that increasing both the current and number of loops will increase the strength of the magnet.
Both BLANKS should be
Increase. When you use the additional battery you will have more voltage and more voltage means more electricity.</span>
<h2>Answer: about the same size of the gap
</h2>
Diffraction happens when a wave (mechanical or electromagnetic wave, in fact, any wave) meets an obstacle or a slit .When this occurs, the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.
Note that the principal condition for the occurrence of this phenomena is that <u>the obstacle must be comparable in size (similar size) to the size of the wavelength.
</u>
<u></u>
In other words, <u>when the gap (or slit) size is larger than the wavelength</u>, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread out greatly.
Therefore:
<h2>
Waves diffract the most when their wavelength is <u>about the same size of the gap</u>
</h2>