Ask question

Ask question

All categories

emmainna [20.7K]

3 years ago

8

A stone is thrown from the ground at a speed of 72km / hr. If the wind barrier is not taken into account, how high will the rock

reach? can anyone help me with step by step

1 answer:

marusya05 [52]3 years ago

5 0

Here's link to the answer:

tinyurl.com/wpazsebu

You might be interested in

A circuit containing an inductor and a capacitor in series is designed to have a resonant frequency of 4511 Hz. If the inductor

OLEGan [10]

Answer:

(e) $6.835\times 10^{-7}F$

Explanation:

At resonance we know that $X_l=X_C$

That is $\omega L=\frac{1}{\omega C}$

$\omega ^2=\frac{1}{LC}$

$\omega =\frac{1}{\sqrt{LC}}$

$f=\frac{1}{2\pi \sqrt{LC}}$

We have given resonance frequency f =4511 Hz and inductance L=1.82 mH

So $4511=\frac{1}{2\pi \sqrt{LC}}$

$LC=\frac{1}{4\pi ^2\times 4511^2}$

$LC=1.244\times 10^{-9}$

$C=\frac{1.244\times 10^{-9}}{1.82\times 10^{-3}}=0.6835\times 10^{-6}=6.835\times 10^{-7}F$

So option e is the correct answer

3 0

3 years ago

A gas occupies a volume of 1.0 m3 in a cylinder at a pressure of 120kPa. A piston compresses the gas until the volume is 0.25m3,

Hoochie [10]

Answer:

Approximately $480\; \rm kPa$ , assuming that this gas is an ideal gas.

Explanation:

Let $V(\text{Initial})$ and $P(\text{Initial})$ denote the volume and pressure of this gas before the compression.
Let $V(\text{Final})$ and $P(\text{Final})$ denote the volume and pressure of this gas after the compression.

By Boyle's Law, the pressure of a sealed ideal gas at constant temperature will be inversely proportional to its volume. Assume that this gas is ideal. By this ideal gas law:

$\displaystyle \frac{P(\text{Final})}{P(\text{Initial})} = \frac{V(\text{Initial})}{V(\text{Final})}$ .

Note that in Boyle's Law, $P$ is inversely proportional to $V$ . Therefore, on the two sides of this equation, "final" and "initial" are on different sides of the fraction bar.

For this particular question:

$V(\text{initial}) = 1.0\; \rm m^3$ .
$P(\text{Initial}) = 120\; \rm kPa$ .

$V(\text{final}) = 0.25\; \rm m^3$ .
The pressure after compression, $P(\text{Final})$ , needs to be found.

Rearrange the equation to obtain:

$\displaystyle P(\text{Final}) = \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})$ .

Before doing any calculation, think whether the pressure of this gas will go up or down. Since the gas is compressed, collisions between its particles and the container will become more frequent. Hence, the pressure of this gas should increase.

$\begin{aligned}P(\text{Final}) &= \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})\\ &= \frac{1.0\; \rm m^{3}}{0.25\; \rm m^{3}} \times 120\; \rm kPa = 480\; \rm kPa\end{aligned}$ .

4 0

4 years ago

A model rocket accelerates at 15.3 m/s2 with a force of 44 N.

melamori03 [73]

To calculate the mass of the body moving, we use Newton's second law of motion which is F = ma where F is the force, m is the mass of the object and a is its acceleration.

F = ma
44 = m(15.3)
m = 2.9 kg

The mass of the rocket would be 2.9 kg.

8 0

3 years ago

Read 2 more answers

A swimming duck paddles the water with its feet once every 1.6 s, producing surface waves with this period. The duck is moving a

emmainna [20.7K]

Answer:

a)

0.245 m/s

b)

0.904 m

Explanation:

a)

$v_{d}$ = speed of duck ahead of wave

$v_{s}$ = speed of surface wave = 0.32 m/s

T = time for paddling = 1.6 s

d = spacing between the waves = 0.12 m

speed of duck ahead of wave is given as

$v_{d}$ = $v_{s}$ - $\frac{d}{T}$

$v_{d}$ = 0.32 - $\frac{0.12}{1.6}$

$v_{d}$ = 0.245 m/s

b)

$v_{w}$ = speed of wave behind the duck

speed of wave behind the duck is given as

$v_{w}$ = $v_{s}$ + $v_{d}$

$v_{w}$ = 0.32 + 0.245

$v_{w}$ = 0.565 m/s

D = spacing between the crests

spacing between the crests is given as

D = $v_{w}$ T

D = (0.565) (1.6)

D = 0.904 m

7 0

3 years ago

If lebron james has a vertical leap of 1.29m, what is his takeoff speed?

BlackZzzverrR [31]

<span>v=u+at</span> <span>
0=5.0283−9.8×t</span><span>
t=0.5130sec</span><span>
Total time = 2t = 1.0261 sec</span>

3 0

3 years ago

Read 2 more answers