All categories

2 years ago

What energy transformation takes place inside an oven?

Physics

2 answers:

Vanyuwa [196]2 years ago

8 0

Answer:

Electrical energy

Explanation:

Iwan ko kung tama pero kung mali im very²x sorry

bagirrra123 [75]2 years ago

6 0

Answer:

electrical energy of when you turn the oven on to thermal energy when it is heating up

You might be interested in

What does 'change only one variable at a time' mean

matrenka [14]

Answer: to only change one factor in an experiment or test

8 0

2 years ago

Pics pls you know what I mean

V125BC [204]

boiiii I wont show you nun

4 0

3 years ago

describe what a person in the passenger seat will fill out the car ages poin describe what a person in the passenger seat will f

dedylja [7]

There are several possibilities. Here are a few that occur to me:

-- If Point-A is the summit of Pike's Peak, he may feel somewhat
short of breath.

-- If Point-A is his grandmother's house, he may feel a great sense
of pleasant anticipation.

-- If Point-A is his office on Monday morning, then he may feel
a tightening sensation in his chest.;

-- If Point-A is his home on Friday afternoon, then he feels the
effects of a slow and steady drop in his blood pressure.

I finer point might be put to it if we had any idea of where
Point-A is, and what it represents in the grand scheme
of things.

5 0

2 years ago

What is the acceleration of an 24 kg object that applies a force of 130N?

WITCHER [35]

Answer:

To find the acceleration of the object we have to apply Newton second law of motion that is F = mass × acceleration.

Explanation:

Given ,

F = 130N

M = 24kg

A = ?

F = m× a

then ,

130N = 24kg ×a

a = 130/24 = 5 m/s.

6 0

1 year ago

9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$