Answer:
334.08 g
Explanation:
87 proof = 43.5%
in 1L of liquid there is 43.5% alcohol/ethanol
1L (43.5/100) = 0.435 L alcohol
we want density in g/L because that's the volume u have
density 0.798 g/mL = 798 g/L
multiply the volume of alcohol by its density to get grams
0.435 L(798 g/L) = 334.08 g
Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.
Answer:
Explanation:
we know that specific heat is the amount of heat required to raise the temperature of substance by one degree mathmeticaly
Q=mcΔT
ΔT=T2-T1
ΔT=26.8-10.2=16.6
C for water is 4.184
therefore
Q=1.00*4.184*16.6
Q=69.4 j
now we have to covert joule into calorie
1 calorie =4.2 j
x calorie=69.4 j/2
so 69.4 j =34.7 calorie thats why 34.7 calorie heat is required to raise the temperature of water from 10.2 to 26.8 degree celsius
Because electricity is just a flow of charge
C is the answer hove a great day