<u>Answer:</u> The concentration of
comes out to be 0.129 M.
<u>Explanation:</u>
To calculate the concentration of base, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is 
We are given:

Putting values in above equation, we get:

Hence, the concentration of
comes out to be 0.129 M.
Fe 3+ + SCN- --> FeSCN 2+
<span>.......Fe 3+ .......SCN-.........FeSCN 2+ </span>
<span>I.......0.04..........0.001.............. </span>
<span>C........-x...............-x............. </span>
<span>E.....0.04-x.....0.001-x...........x </span>
<span>Keq = 203.4 = x / (0.04-x)(0.001-x) </span>
<span>203.4 = x / (x^2 - 0.041x + 4x10^-5) </span>
<span>203.4x^2 - 8.34x + 0.00094 = x </span>
<span>203.4x^2 - 9.34x + 0.00094 = 0 </span>
<span>x = -0.0001M or 0.0458M </span>
<span>so, using your Keq, there would be no SCN- or Fe 3+ left.....all would be in the form of FeSCN 2+</span>
The density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml
<h3>What is density?</h3>
Density is the measurement of how tightly a material is packed together.
Given data:
Weight =7.553g
Volume = 10.0ml
Density =
Density =
Density = 0.7553 g/ml
Hence, the density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml.
Learn more about density here:
brainly.com/question/15164682
#SPJ1
Answer:
v = 46.5 m/s
Explanation:
Given data:
Mass of car = 1210 kg
Momentum of car = 56250 kg m/s
Velocity of car = ?
Solution:
Formula:
p = mv
p = momentum
m = mass
v = velocity
Now we will put values in formula:
56250 kg m/s = 1210 kg × v
v = 56250 kg m/s / 1210 kg
v = 46.5 m/s
So a car having mass of 1210 kg with momentum 56250 kg m/s having 46.5 m/s velocity.
The water cycle shows the continuous movement of water within the Earth and atmosphere. It is a complex system that includes many different processes. Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow.
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>