All categories

2 years ago

What happens when ethane gas is passed though alkaline KMnO4 solution

2 answers:

8 0

Answer : When ethylene is passed through alkaline KMnO4 solution 1, 2-Ethanediol is formed. The Purple color of KMnO4 decolorizes.

Vinvika [58]2 years ago

8 0

Explanation:

जब एथनॉल को क्षारीय पोटेशियम परमैंगनेट के घोल से गर्म किया जाता है तो यह इथेनोइक अम्ल में परिवर्तित हो जाता है। इस अभिक्रिया में क्षारीय पोटैशियम परमैंगनेट निम्नानुसार कार्य करता है:

You might be interested in

Compute the equilibrium constant at 25 ∘C for the reaction between Sn2+(aq) and Cd(s), which form Sn(s) and Cd2+(aq). Express yo

Radda [10]

Answer:

6.1×10^8

Explanation:

The reaction is;

Sn^2+(aq) + Cd(s) -----> Sn(s) + Cd^2+(aq)

E°cell = E°cathode - E°anode

E°cathode= -0.14 V

E°anode= -0.40 V

E°cell = -0.14-(-0.40)

E°cell= -0.14+0.40

E°cell= 0.26 V

But

E°cell= 0.0592/n log K

E°cell= 0.0592/2 log K

0.26= 0.0296log K

log K = 0.26/0.0296

log K= 8.7838

K= Antilog (8.7838)

K= 6.1×10^8

8 0

3 years ago

A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an

mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation : Given,

Concentration of $H_2$ at equilibrium = 0.067 mol

Concentration of $CO$ at equilibrium = 0.021 mol

Concentration of $CH_3OH$ at equilibrium = 0.040 mol

The given chemical reaction is:

$CO+2H_2\rightarrow CH_3OH$

The expression for equilibrium constant is:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}$

$K_c=424.3$

Thus, the value of equilibrium constant (K) is, 424.3

4 0

3 years ago

9. To become like a noble gas the element P will have a charge of

MrRa [10]

Answer:

to become a noble gas element P will have 2 electrons in it's outer most energy level if it has one energy level

and eight in the last energy level if more than one

6 0

3 years ago

5 point<br> How many molecules are in 50g of CO2?

Alex73 [517]

Answer:

The answer is 44.0095 molecules

7 0

3 years ago

Read 2 more answers

Calculate the number of C atoms in 0.190 mole C6H14O.<br> can anyone help me on this one?

likoan [24]

In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6* $10^{23}$ (atoms of C in one mole) = 6.84* $10^{23}$ atoms.

8 0

3 years ago

What happens when ethane gas is passed though alkaline KMnO4 solution​

What happens when ethane gas is passed though alkaline KMnO4 solution