1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nutka1998 [239]
3 years ago
8

Given two points P(sinθ+2, tanθ-2) and Q(4sin²θ+4sinθcosθ+2acosθ, 3sinθ-2cosθ+a). Find constant "a" and the corresponding value

of θ when these two points coincide. (0 ≤ θ < 2π)
Show your work, thanks!​
Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

\rm\displaystyle \displaystyle \displaystyle θ=    {60}^{ \circ} , {300}^{ \circ}

\rm \displaystyle a =    - \frac{   \sqrt{3} }{2}    - 1, \frac{\sqrt{3}}{2}  - 1

Step-by-step explanation:

we are given two <u>coincident</u><u> points</u>

\displaystyle  P( \sin(θ)+2,  \tan(θ)-2)   \: \text{and } \\  \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)

since they are coincident points

\rm \displaystyle  P( \sin(θ)+2,  \tan(θ)-2)    = \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ )\cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)

By order pair we obtain:

\begin{cases}  \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ) =  \sin( \theta)   + 2 \\   \\  \displaystyle 3 \sin( \theta)  - 2  \cos( \theta)  + a =  \tan( \theta)  - 2\end{cases}

now we end up with a simultaneous equation as we have two variables

to figure out the simultaneous equation we can consider using <u>substitution</u><u> method</u>

to do so, make a the subject of the equation.therefore from the second equation we acquire:

\begin{cases}  \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sinθ \cos(θ)+2a \cos(θ )=  \sin( \theta)   + 2 \\   \\  \boxed{\displaystyle  a =  \tan( \theta)  - 2 - 3 \sin( \theta)   +  2  \cos( \theta) } \end{cases}

now substitute:

\rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2 \cos(θ) \{\tan( \theta)  - 2 - 3 \sin( \theta)   +  2  \cos( \theta)   \}=  \sin( \theta)   + 2

distribute:

\rm\displaystyle \displaystyle 4 \sin ^{2}( θ)+4 \sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta)  - 6 \sin( \theta) \cos( \theta)    + 4  \cos ^{2} ( \theta)   =  \sin( \theta)   + 2

collect like terms:

\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta)     + 4  \cos ^{2} ( \theta)   =  \sin( \theta)   + 2

rearrange:

\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) + 4 \cos ^{2} ( \theta)  - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + =  \sin( \theta)   + 2

by <em>Pythagorean</em><em> theorem</em> we obtain:

\rm\displaystyle \displaystyle 4  - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta)  =  \sin( \theta)   + 2

cancel 4 from both sides:

\rm\displaystyle \displaystyle   - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta)  =  \sin( \theta)    - 2

move right hand side expression to left hand side and change its sign:

\rm\displaystyle \displaystyle   - 2\sin(θ) \cos(θ)+\sin(θ ) - 4\cos( \theta) + 2  =  0

factor out sin:

\rm\displaystyle \displaystyle  \sin (θ) (- 2 \cos(θ)+1) - 4\cos( \theta) + 2  =  0

factor out 2:

\rm\displaystyle \displaystyle  \sin (θ) (- 2 \cos(θ)+1)  + 2(- 2\cos( \theta) + 1 ) =  0

group:

\rm\displaystyle \displaystyle ( \sin (θ)   + 2)(- 2 \cos(θ)+1)  =  0

factor out -1:

\rm\displaystyle \displaystyle -  ( \sin (θ)   + 2)(2 \cos(θ) - 1)  =  0

divide both sides by -1:

\rm\displaystyle \displaystyle   ( \sin (θ)   + 2)(2 \cos(θ) - 1)  =  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we acquire:

\begin{cases}\rm\displaystyle \displaystyle   \sin (θ)   + 2 = 0 \\ \displaystyle2 \cos(θ) - 1=  0 \end{cases}

cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta

\begin{cases}\rm\displaystyle \displaystyle   \sin (θ)     \neq  - 2 \\ \displaystyle2 \cos(θ) =  1\end{cases}

divide both sides by 2:

\rm\displaystyle \displaystyle \displaystyle \cos(θ) =   \frac{1}{2}

by unit circle we get:

\rm\displaystyle \displaystyle \displaystyle θ=    {60}^{ \circ} , {300}^{ \circ}

so when θ is 60° a is:

\rm \displaystyle a =  \tan(  {60}^{ \circ} )  - 2 - 3 \sin(  {60}^{ \circ} )   +  2  \cos(  {60}^{ \circ} )

recall unit circle:

\rm \displaystyle a =   \sqrt{3}  - 2 -  \frac{ 3\sqrt{3} }{2}   +  2   \cdot  \frac{1}{2}

simplify which yields:

\rm \displaystyle a =    - \frac{   \sqrt{3} }{2}    - 1

when θ is 300°

\rm \displaystyle a =  \tan(  {300}^{ \circ} )  - 2 - 3 \sin(  {300}^{ \circ} )   +  2  \cos(  {300}^{ \circ} )

remember unit circle:

\rm \displaystyle a =  -  \sqrt{3}   - 2  +   \frac{3\sqrt{ 3} }{2}  +  2   \cdot  \frac{1}{2}

simplify which yields:

\rm \displaystyle a = \frac{ \sqrt{3} }{2} - 1

and we are done!

disclaimer: also refer the attachment I did it first before answering the question

You might be interested in
Micah was given $200 for his birthday. Each week he spends $15 on comic books. In how many weeks will his birthday
Semenov [28]

Answer:

Step-by-step explanation:

no I belive 200 divide 15 is 13 i might be du,mb

8 0
2 years ago
Read 2 more answers
In the United States 5 million Farmers provide food for 260 million people
ycow [4]
If I am understanding the question correctly, farmers make up .02% (rounded to the nearest hundredth, full answer is .0192307) of the population. I calculated this by dividing 5,000,000 by 260,000,000. I then moved my decimal over 2 places to the right to convert it to a percent.
6 0
3 years ago
3+12x5/(5+15) What’s the answer
r-ruslan [8.4K]

\bf 3+12\times \cfrac{5}{(5+15)}\implies 3+12\times \cfrac{5}{\underset{\uparrow }{20}}\implies 3+12\times \cfrac{1}{4}\implies 3+\cfrac{\stackrel{\downarrow }{12\times 1}}{4} \\\\\\ 3+\cfrac{12}{4}\implies 3+\stackrel{\downarrow }{3}\implies 9

3 0
3 years ago
Read 2 more answers
At a high school, the length of a class period is 40 minutes. What is the length, in hours, of a class period at the high school
olga2289 [7]

Answer:

40 minutes

2/3 hours

0.667 hour

2,400 seconds

Step-by-step explanation:

5 0
3 years ago
How many hundredths in 4.97
Oksanka [162]
7 is in the hundredths place.
There are 7 one hundredths.
7 0
3 years ago
Read 2 more answers
Other questions:
  • Can someone write the point slope equation
    8·1 answer
  • I need help with this question
    11·2 answers
  • HELP
    15·1 answer
  • Trials in an experiment with a polygraph include results that include cases of wrong results and cases of correct results. Use a
    10·1 answer
  • The speed of a river current is 8 mph. If a boat travels 20 miles downstream in the same time that it takes to travel 10 miles​
    9·1 answer
  • Solve for x 5x-4_&gt;12 and 12x+5&lt;_-4
    13·1 answer
  • Five more than twice a number is -13. Find the number.<br><br>helpp
    12·1 answer
  • PLEASEEEE HELPP MEE WITHHH NUMBERRR 10!!!!!!<br> PLEASSEEE AND I NEED A GREAT EXPLANATIOn
    12·1 answer
  • Solve thye inequality 2/3x - 1/6 &gt; 1/2
    9·1 answer
  • What is the measurment of the angle TRS?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!