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yawa3891 [41]
2 years ago
6

The speed of an aircraft is measure in the unit_​

Physics
1 answer:
slega [8]2 years ago
8 0

Answer:

knot...

.....

.....

.....

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A gas occupies 0.60 m3 at a 5.0 atm. If the temperature of the gas remains the same and the pressure decreases to 2.5 atm, what
Naddika [18.5K]

Answer:

its 6 :) hdgdgsvhdhs

Explanation:

hdhdhscdhsjsvdjsjwjshd

8 0
3 years ago
Calculate the weight of a 1 kg mass at earth's surface. The mass of the of the Earth's surface if the mass of the earth is 6 x 1
yuradex [85]

Answer:

9.8N

Explanation:

Here we can get gravitational acceleration according to the place where object is placed by bellow equation

g = GM/R²

g - Gravitational Acceleration

G - Gravitational constant (6.67×10-11)

R - Distance ( Radius )

g = 6.67 × 10-11 × 1024 /(6.37×106)²

g = 9.8 m/s²

There for

Weight = Mass × Gravitational acceleration

= 1×9.8

= 9.8 N

4 0
3 years ago
Why is the SI measurement system so important to the scientific community?
navik [9.2K]
It creates a stable foundation that allows for free communication between languages and cultures when describing nature using mathematics. The SI units of measurement can be seen as a kind of global language of logic and reason, separate from culture. It unifies mankind in understanding one another.
7 0
3 years ago
WILL MARK BRAINLIEST PLEASE HELP AND SHOW ALL WORK
jok3333 [9.3K]

Answer:

Same reading.

Explanation:

Assume that after the string breaks the ball falls through the liquid with constant speed. If the mass of the bucket and the liquid is 1.20 kg, and the mass of the ball is 0.150 kg,

A.) Before the string break, the total weight = weight of the can + weight of the water.

According to Archimedes' Principle which state that: “A body immersed in a liquid loses weight by an amount equal to the weight of the liquid displaced.” Archimedes principle also states that: “When a body is immersed in a liquid, an upward thrust, equal to the weight of the liquid displaced, acts on it

B.) After the string break.

The scale will have the same reading as before the string break.

6 0
3 years ago
Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m
Reil [10]

Answer:

\Delta l=0.015m

Explanation:

We have given initial length of the steel guitar l = 1 m

Cross sectional area A=0.5mm^2=0.5\times 10^{-6}m^2

Young's modulus \gamma=2\times 10^{11}Pa

Force F = 1500 N

So stress =\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa

We know that young's modulus =\frac{stress}{strain}

So 2\times 10^{11}=\frac{3\times 10^{9}}{strain}

strain=1.5\times 10^{-2}=0.015m

Now strain =\frac{\Delta l}{l}

0.015=\frac{\Delta l}{1}

\Delta l=0.015m

6 0
3 years ago
Read 2 more answers
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