Heres the answer to your question
The empirical formula is obtained by calculating the mole ratios of the atoms in the elements.
The number of moles =mass/ R.A.M
For hydrogen, no. of moles=8/1=8
For oxygen, no. Of moles=64/16=4
The tabular solution is attached.
Pressures oxygen and hydrogen + pressure nitrogen
110 Kpa + 106 Kpa = 216 Kpa
Partial pressure:
total pressure - exerted by nitrogen:
282 Kpa - 216 Kpa
= 66 Kpa
hope this helps!