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icang [17]
3 years ago
10

Is

Physics
2 answers:
aliya0001 [1]3 years ago
5 0

Answer:

The answer is 30.8 (J)

Explanation:

You're welcome

viktelen [127]3 years ago
3 0

Kinetic energy = 29.912 J

<h3>Further explanation</h3>

Given

mass = 0.155 kg

vo=initial velocity = 31.4 m/s

h/d=30 m

Required

KE=kinetic energy

Solution

vt²=vo²-2ad⇒vt=final velocity

vt²=31.4²-2.10.30⇒g=10 m/s²

vt²=985.96-600

vt²=385.96 m/s

Kinetic  energy (KE)

\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 0.155.\times 385.96\\\\KE=29.912~J

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Convert 3 hours 21 minutes to decimal hours.
Oxana [17]

Total hours is 3.35 hours

<u>Explanation:</u>

Given:

convert 3 hours 21 minutes to decimal hours

We know:

1 hour = 60 minutes

and

1 minute = 60 seconds

1 minute = 1 / 60 hours

So,

21 minutes = \frac{21}{60} hours

                  = 0.35 hours

Total hours would be = 3 hours + 0.35 hours

                                    = 3.35 hours

Therefore, total hours is 3.35 hours

7 0
3 years ago
Two Earth satellites, A and B, each of mass m = 940 kg , are launched into circular orbits around the Earth's center. Satellite
-Dominant- [34]

Answer:

The required work done is 6.5\times10^{9}\ J

Explanation:

Given that,

Mass of each satellites = 940 kg

Altitude of A = 4500 km

Altitude of B = 11100 km

We need to calculate the potential energy

Using formula of potential

U_{A}=-\dfrac{Gm_{A}m_{E}}{r_{A}}

Put the value into the formula

U_{A}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+4.50\times10^{6}}

U_{A}=-3.44\times10^{10}\ J

We need to calculate the potential energy

Using formula of potential

U_{B}=-\dfrac{Gm_{B}m_{E}}{r_{A}}

Put the value into the formula

U_{B}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+11.10\times10^{6}}

U_{B}=-2.14\times10^{10}\ J

We need to calculate the value of k_{A}

Using formula of k_{A}

k_{A}=-\dfrac{1}{2}U_{A}

Put the value into the formula

k_{A}=\dfrac{1}{2}\times3.44\times10^{10}

k_{A}=1.72\times10^{10}\ J

We need to calculate the value of k_{B}

Using formula of k_{B}

k_{B}=-\dfrac{1}{2}U_{B}

Put the value into the formula

k_{B}=\dfrac{1}{2}\times2.14\times10^{10}

k_{B}=1.07\times10^{10}\ J

We need to calculate the work done

Using formula of work done

W=\Delta K+\Delta U

W=(k_{B}-k_{A})+(U_{B}-U_{A})

W=(-\dfrac{U_{B}}{2}+\dfrac{U_{A}}{2})+(U_{B}-U_{A})

W=\dfrac{1}{2}(U_{B}-U_{A})

Put the value into the formula

W=\dfrac{1}{2}\times(-2.14\times10^{10}+3.44\times10^{10})

W=6.5\times10^{9}\ J

Hence, The required work done is 6.5\times10^{9}\ J

7 0
3 years ago
A trooper is moving due south along the freeway at a speed of 23 m/s. at time t = 0, a red car passes the trooper. the red car m
Deffense [45]
The answer choice is 23
4 0
4 years ago
The potential energy for a mass on a spring is proportional to the square of which of these quantities? A. mass B. frequency C.
frutty [35]
<h2>Answer:Displacement</h2>

Explanation:

Potential energy is present in a spring because the spring is elongated and some work is done it to elongate it.

The elastic potential energy present in a spring is given by kx^{2}

where k is the spring constant.It may vary from spring to spring and x is the displacement of the spring from its equalibrium position.

It is evident from the equation that potential energy in the spring increases as x^{2} increases.

3 0
3 years ago
Two children stand on a platform at the top of a curving slide next to a backyard swimming pool. At the same moment the smaller
FinnZ [79.3K]

Answer:

THE KINETIC ENERGY OF THE SMALLER CHILD IS LESS THAN THAT OF THE BIGGER CHILD

Explanation: Kinetic energy is the energy that is exerted on a body that is in motion, kinetic energy is affected by both the mass of the object and the velocity of the object.

Mathematically,Kinetic energy is represented as follows;

K.E=1/2MV^{2}

Where M represents the mass of the object in kilograms and V represents velocity of the moving object measured in meters per seconds.

The higher the weight of the object the higher the kinetic energy of the object which means the bigger child will have a higher kinetic energy than the smaller child.

7 0
3 years ago
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