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2 years ago

This occurs when a person comes into contact with hazard

Physics

1 answer:

atroni [7]2 years ago

8 0

Answer:

Exposure occurs when a person comes into contact with hazard

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Explain the effects of force giving example

Pie

Answer:

1) Can change the state of an object(rest to motion/ motion to rest):For example, pushing a heavy stone in order to move it. 2) May change the speed of an object if it is already moving. 4) May bring about a change in the shape of an object. For example, blowing air in balloon.

3 0

2 years ago

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A basketball is shot at 14.0 m/s at a 65.0 degree angle. What is the magnitude only (no direction) of the velocity of the ball 2

Alex787 [66]

Answer:

10.4 m/s

Explanation:

I just know it's right!

8 0

3 years ago

A car battery has a rating of 170 ampere-hours. This rating is one indication of the total charge that the battery can provide t

Pavlova-9 [17]

Answer:

612000 C

Explanation:

Current, I, is given as the rate of flow of charge, that is:

I = Δq / Δt

where q = electric charge

t = time taken

This implies that:

Δq = I * Δt

The battery rating is 170 Ampere-hours, therefore:

Δq = 170 * 1 hour

But 1 hour = 3600 seconds;

=> Δq = 170 * 3600 = 612000 C

The total charge that the battery can provide is 612000 C.

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3 years ago

A 16.0kg canoe moving to the left at 12.5m/s makes an elastic head-on collision with a 14.0kg raft moving to the right at 16.0m/

kherson [118]

The canoe is moving at 14.1 m/s to the right after the collision.

Explanation:

According to the law of conservation of momentum, in absence of external forces the total momentum of the system must be conserved before and after the collision. So we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where:

$m_1 = 16.0 kg$ is the mass of the canoe

$u_1 = -12.5 m/s$ is the initial velocity of canoe (we take right as positive direction, and since the canoe is moving to the left, its velocity is negative)

$v_1$ is the final velocity of the canoe

$m_2 = 14.0 kg$ is the mass of the raft

$u_2 = +16.0 m/s$ is the initial velocity of the raft

$v_2 = -14.4 m/s$ is the final velocity of the raft

Re-arranging the equation and substituting the values, we find: the final velocity of the canoe:

$v_1 = \frac{m_1 u_1 + m_2 u_2-m_2 v_2}{m_1}=\frac{(16.0)(-12.5)+(14.0)(16.0)-(14.0)(-14.4)}{16.0}=+14.1 m/s$

So, the canoe is moving at 14.1 m/s to the right after the collision.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

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brainly.com/question/9484203

#LearnwithBrainly

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3 years ago

2. What is the standard value of acceleration due to gravity or "g"?

svp [43]

Answer:

The standard acceleration due to gravity (or standard acceleration of free fall), sometimes abbreviated as standard gravity, usually denoted by ɡ0 or ɡn, is the nominal gravitational acceleration of an object in a vacuum near the surface of the Earth. It is defined by standard as 9.80665 m/s2 (about 32.17405 ft/s2).

Explanation:

6 0

3 years ago

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This occurs when a person comes into contact with hazard​

This occurs when a person comes into contact with hazard