Answer:
a = 40
b = 29
Explanation:
Give a place holder for the numbers that we don't know.
Lets call the two numbers a and b.
From the given info, we can write an expression and solve it:
"one number is 11 more than another number"
a = 11 + b
from this, we know that a > b.
''three times the larger number exceeds four times the smaller number by 4"
3a = 4b + 4
Now we have 2 equations, we can use them to solve using whatever method you want.
a = 11 + b
3a = 4b + 4
I will be using matrices RREF to solve for this.
a - b = 11
3a - 4b = 4
![\begin{bmatrix}1 & -1 & 11\\3 & -4 & 4 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D1%20%26%20-1%20%20%26%2011%5C%5C3%20%26%20-4%20%26%204%20%5Cend%7Bbmatrix%7D)
![\begin{bmatrix}1 & 0 & 40\\0 & 1 & 29 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D1%20%26%200%20%20%26%2040%5C%5C0%20%26%201%20%26%2029%20%5Cend%7Bbmatrix%7D)
a = 40
b = 29
Answer:
The idle speed of a running compression should be between 50-75 PSI and that is about half of the static compression.
Explanation:
The Running or Dynamic compression is used to determine how well the cylinder in an engine is absorbing air, reserving it for the proper length of time, and releasing it to the exhaust. The static or cranking compression test is used to check the sealing of the cylinder. Before performing the running compression test, the static compression test is first performed to rule out other issues like bent valves.
The standard value for the static compression is given by;
Compression ratio * 14.7 = Manufacturers Specification
The running compression should always be half of the static compression.
Answer:
Explanation:if you stretch the hose more tightly the speed of the pulse will reduce..
Answer:
N = 38546.82 rpm
Explanation:
= 150 mm
![A_{1}= \frac{\pi }{4}\times 150^{2}](https://tex.z-dn.net/?f=A_%7B1%7D%3D%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5Ctimes%20150%5E%7B2%7D)
= 17671.45 ![mm^{2}](https://tex.z-dn.net/?f=mm%5E%7B2%7D)
= 250 mm
![A_{2}= \frac{\pi }{4}\times 250^{2}](https://tex.z-dn.net/?f=A_%7B2%7D%3D%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5Ctimes%20250%5E%7B2%7D)
= 49087.78 ![mm^{2}](https://tex.z-dn.net/?f=mm%5E%7B2%7D)
The centrifugal force acting on the flywheel is fiven by
F = M (
-
) x
------------(1)
Here F = ( -UTS x
+ UCS x
)
Since density, ![\rho = \frac{M}{V}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cfrac%7BM%7D%7BV%7D)
![\rho = \frac{M}{A\times t}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cfrac%7BM%7D%7BA%5Ctimes%20t%7D)
![M = \rho \times A\times t](https://tex.z-dn.net/?f=M%20%3D%20%5Crho%20%5Ctimes%20A%5Ctimes%20t)
![M = 7100 \times \frac{\pi }{4}\left ( D_{2}^{2}-D_{1}^{2} \right )\times t](https://tex.z-dn.net/?f=M%20%3D%207100%20%5Ctimes%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5Cleft%20%28%20D_%7B2%7D%5E%7B2%7D-D_%7B1%7D%5E%7B2%7D%20%5Cright%20%29%5Ctimes%20t)
![M = 7100 \times \frac{\pi }{4}\left ( 250^{2}-150^{2} \right )\times 37](https://tex.z-dn.net/?f=M%20%3D%207100%20%5Ctimes%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5Cleft%20%28%20250%5E%7B2%7D-150%5E%7B2%7D%20%5Cright%20%29%5Ctimes%2037)
![M = 8252963901](https://tex.z-dn.net/?f=M%20%3D%208252963901)
∴
-
= 50 mm
∴ F = ![763\times \frac{\pi }{4}\times 250^{2}-217\times \frac{\pi }{4}\times 150^{2}](https://tex.z-dn.net/?f=763%5Ctimes%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5Ctimes%20250%5E%7B2%7D-217%5Ctimes%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5Ctimes%20150%5E%7B2%7D)
F = 33618968.38 N --------(2)
Now comparing (1) and (2)
![33618968.38 = 8252963901\times 50\times \omega ^{2}](https://tex.z-dn.net/?f=33618968.38%20%3D%208252963901%5Ctimes%2050%5Ctimes%20%5Comega%20%5E%7B2%7D)
∴ ω = 4036.61
We know
![\omega = \frac{2\pi N}{60}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7B2%5Cpi%20N%7D%7B60%7D)
![4036.61 = \frac{2\pi N}{60}](https://tex.z-dn.net/?f=4036.61%20%3D%20%5Cfrac%7B2%5Cpi%20N%7D%7B60%7D)
∴ N = 38546.82 rpm
That is a thread ball valves