So we can now calculate the area of the wire
We need also the resistivity specific of cupper, that is:
a) We have to calculate the current that is given by,
b)
c) current density
d) Rate of thermal energy
Answer:
8.8 cm
31.422 cm/s
Explanation:
m = Mass of block = 0.6 kg
k = Spring constant = 15 N/m
x = Compression of spring
v = Velocity of block
A = Amplitude
As the energy of the system is conserved we have
Amplitude of the oscillations is 8.8 cm
At x = 0.7 A
Again, as the energy of the system is conserved we have
The block's speed is 31.422 cm/s
Answer:
See Explanation
Explanation:
Solving (4): 0.84554 as a fraction
The above number is to 5 decimal places, so the fraction equivalent is:
Divide numerator and denominator by 2
Solving (5):
The midpoint, M is calculated as follows:
Where
The distance, D is calculated using:
Solving (1): The expression for f(x) is not clear. So, I'll make use of:
Substitute each value of the domain in
The range is:
Solving (2):
Shape: Open Cylinder
The surface area is calculated as:
Solving (3):
The value of a is not clear. So, I'll assume that a is a
Given that
Find
Substitute 3a for b
Absolute value of 4a is 4a. So,
Solving (9):
Given
--- Principal
--- Rate
--- Time in years
The amount (A) is calculated as follows:
Hence, the amount at the end of 2 years is: