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daser333 [38]
3 years ago
13

Hello guys, differentiate between vapourisation and evaporation

Chemistry
2 answers:
Darya [45]3 years ago
8 0

Answer:

vapourisation can occur from solid or liquid into a gas but evaporation is straight from a liquid and is often below boiling temperature while vapourisation is often above boiling temperature

masya89 [10]3 years ago
4 0

Answer:

\huge\red{\boxed{\mathfrak{Hello}}}

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<h3><u>Differences</u><u> between Vaporization & </u><u>Evaporation:</u><u>-</u></h3>

<u>{\huge\pink{\fbox{{࿐αɴѕωєя࿐}}}}</u>

\huge\green{ \mid{ \underline{ \overline{ \tt  PARAMETERS: }} \mid}}

  1. Definition
  2. Transition of state
  3. Speed of process
  4. Effect area
  5. Movement of molecule

\huge\purple{ \mid{ \underline{ \overline{ \tt  VAPORIZATION: }} \mid}}

  1. It is defined as the transitional phase of a compound or an element at the boiling temperature.
  2. It changes the state of matter from a solid or liquid to a gas.
  3. It is generally happening at a fast pace and also it needs less amount of energy.
  4. During the vaporization process, all of the water turns into a gas.
  5. During vaporization, molecules may come from below the surface of liquid also.

\huge\orange{ \mid{ \underline{ \overline{ \tt  EVAPORATION:}} \mid}}

  1. It is nothing but a special kind of vaporization and mostly occurring at the temperature below the boiling point.
  2. It changes the liquid state of the matter directly into a gas.
  3. It is generally a slower process that needs more energy.
  4. During the evaporation process, only the top level of water turn into gas.
  5. During evaporation, molecules vaporize from the surface of liquid only.

➳ ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

\huge\pink{ \mid{ \underline{ \overline{ \tt ꧁❣ RainbowSalt2222 ࿐ }} \mid}}

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Metals react with oxygen to give oxides with the general formula MxOy. What is a balanced chemical equation for the reaction of
katovenus [111]

Answer: 4Fe+3O_2\rightarrow 2Fe_2O_3

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here iron is having an oxidation state of +3 called as Fe^{3+} cation and oxide O^{2-} is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Fe_2O_3.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2Fe+3O_2\rightarrow 2Fe_2O_3

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3 years ago
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Explain why the standard enthalpy of formation () for Cl2 (g) is zero, but its standard entropy is larger than zero.
Galina-37 [17]

The standard enthalpy of formation for chlorine is zero but the standard entropy is larger than 0 because it is the elemental state of chlorine.

The standard enthalpy of formation for chlorine is zero because cl2 is the elemental state of chlorine and it does not require any energy for the formation of the standard state of chlorine.

The entropy of any system cannot be negative. It can only be positive or zero.

The entropy of a system will become zero only at a absolute zero temperature.

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In the reaction 2Mg (s) + O2 (g) + 2H2O (l) → 2Mg2+ (aq) + 4OH– (aq), which substance is reduced?
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<em>No O atoms are present</em> as reacting substances, only O_2 and H_2O molecules.

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We must use <em>oxidation numbers</em> to decide whether oxygen or water is the substance reduced.

The oxidation number of O changes from 0 in O_2 to -2 in OH^(-).

A decrease in oxidation number is <em>reduction</em>, so O_2 is the substance  reduced.

The oxidation number of O is -2 in both H_2O and OH^(-), so water is <em>neither oxidized nor reduced</em>.

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