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adelina 88 [10]
3 years ago
6

Can someone help with me 1,2,3 please I will mark brainless .

Physics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

1) A. .33 hr

2) B. 6ft

3) A. 58mi/hr

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A bowling ball with a mass of 9kg is thrown down a lane with a constant speed of 3 m/s. The ball hits the 1.5kg pin, initially a
olasank [31]

Answer:

M1 V1 = M1 V2 + M2 V3    conservation of momentum

V2 = (M1 V1 - M2 V3) / M1      where V2 = speed of M1 after impact

V2 = (3 * 9 - 1.5 * 5) / 9  =   (27 - 7.5) / 9 = 2.17 m/s

Note: All speeds are in the same direction and have the same sign

7 0
2 years ago
What is 12 and 1 half % expressed as a fraction
kiruha [24]
12 1/2 i would assume
6 0
3 years ago
Read 2 more answers
Seema knows the mass of a basketball. What other information is needed to find the ball’s potential energy?
adelina 88 [10]

Potential energy can be found using this formula:

PE= m * g * h

where:

PE= potential energy

m=mass

g=gravitational acceleration constant (9.8 m/s^2)

h= height

So your answer is height because you also use the gravitational constant.

7 0
3 years ago
The formula $F = \frac{9}{5} C + 32$ can be used to convert temperatures between degrees Fahrenheit ($F$) and degrees Celsius ($
slamgirl [31]

Answer:

-30° C

Explanation:

Data provided in the problem:

The formula for conversion as:

F  = (9/5)C + 32

Now,

for the values of F = -22 , C = ?

Substituting the value of F in the above formula, we get

-22 = (9/5)C + 32

or

-22 - 32 = (9/5)C

or

(9/5)C = - 54

or

C = - 54 × (5/9)

or

C = - 30 °

Hence, -22 Fahrenheit equals to -30°C

7 0
3 years ago
Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?
MrMuchimi
 T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r 

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance. 
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect, 

Point 1: 
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m 
The distance between the two points then is equal to 7.07 m.


</span>
8 0
3 years ago
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