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3 years ago

Predict Phenomena A positively charged particle is placed next to an

Physics

1 answer:

lozanna [386]3 years ago

7 0

Answer:

The positively charged particle will move towards the negatively charged particle.

Explanation:

According to Coulomb's Law, there are two types of charges--positive charge and negative charge. Coulomb said that they are either attractive or repulsive but the basic law in charges states that opposite attracts. Since they (the two charged objects) are oppositely charged, they will then move towards one another.

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stira [4]

Answer:

$4.81*10^{29}J$

Explanation:

Since the formula for kinetic energy of an object is:

$E_k = \frac{mv^2}{2}$

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3 years ago

How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?

Nuetrik [128]

a = ( V2 - V1)/( t2 - t1)
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3 years ago

Read 2 more answers

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shtirl [24]

Answer:

Power= 0.5hp = 375W

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3 years ago

A 2 kg ball is moving 3 m/s when it starts rolling up a hill.

AURORKA [14]

Answer:

the height reached is = 0.458 [m]

Explanation:

We need to make a sketch of the ball and see the location of the reference point where the potential energy is zero. But the kinetic energy will be defined by the following expression:

$Ek=\frac{1}{2} *m*v^{2} \\where:Ek= kinetic energy [J]\\m = mass of the ball [kg]\\v = velocity of the ball [m/s]$

Replacing the values on the equation we have:

$Ek=\frac{1}{2}*(2)*(3^{2} )\\ Ek=9[J]\\$

This kinetic energy will be transformed in potential energy in the moment when the ball starts to rolling up. Therefore the maximum height reached by the ball depends of the initial velocity given to the ball.

$Ek=Ep\\where\\Ep=potential energy [J]\\Ep=m*g*h\\where\\g=gravity = 9.81[m/s^2]\\h=height reached [m]\\$

Now we have:

$h=\frac{Ep}{m*g} \\h=\frac{9}{2*9.81} \\\\h=0.45 [m]$

In that moment when the ball reach the 0.45 [m] the potencial energy will be maximum and equal to the kinetic energy when the ball has a velocity of 3[m/s]

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