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Nataliya [291]
3 years ago
15

Which is correct about the charge movement when a battery is connected to copper wire?a.)Electrons leave the positive battery te

rminal and electrons enter the negative terminal. b.)Electrons leave the negative battery terminal and electrons enter the positive terminal. c.)Protons leave the positive battery terminal and positive charges enter the negative terminal. d.)Protons leave the negative battery terminal and positive charges enter the positive terminal.
Physics
1 answer:
professor190 [17]3 years ago
5 0

Answer:

b.)Electrons leave the negative battery terminal and electrons enter the positive terminal.

Explanation:

- First of all, the carriers of charge in an electrical circuit are the electrons, not the protons. In fact, electrons in a conductor (such as the copper wire) are free to move, while protons are bond inside the nuclei of the atoms, so they are not free to move. This means that only choices a) and b) could be correct.

- Finally, we know that charges with same sign repel each other, while charges with opposite sign attract each other. This means that electrons are repelled by the negative terminal of the battery and attracted by the positive terminal of the battery. Therefore, the correct choice must be

b.)Electrons leave the negative battery terminal and electrons enter the positive terminal.

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A student attaches a block to a vertical spring so that the block-spring system will oscillate if the block-spring system is rel
vodka [1.7K]

Answer:

Time period of the motion will remain the same while the amplitude of the motion will change

Explanation:

As we know that time period of oscillation of spring block system is given as

T= 2\pi\sqrt{\frac{M}{k}}

now we know that

M = mass of the object

k = spring constant

So here we know that the time period is independent of the gravity

while the maximum displacement of the spring from its mean position will depends on the gravity as

mg = kx

x = \frac{mg}{k}

so we can say that

Time period of the motion will remain the same while the amplitude of the motion will change

4 0
3 years ago
Which of the following does NOT support the geologic evidence used to date the earth?
Zanzabum

Answer:

comparing the anatomy of organisms

Explanation:

Basically, Rocks are the solid evidence used to date the earth.

Due to the changing in the genetic make up of organisms,the anatomy of organisms is not a reliable evidence to date the earth.

4 0
3 years ago
What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?
Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

Here

g_{eff}= g

Now by putting the values

T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}

T=1.37 s

b)

Free falling elevator :

When elevator is falling freely then

g_{eff}= 0            ( This is case of weightless motion)

Therefore

T=2\pi\sqrt{ \dfrac{L}{0}

T=∞  (Infinite)

6 0
4 years ago
what can accurately be said about a resultant wave that displays both reinforcement and interference?
schepotkina [342]
<span>As the frequency of the waves increases, a greater number of wavelengths pass a given point per second. From the wave formula, we see that there is an indirect relationship between frequency and the wavelength. thus, as the frequency increases the wavelength decreases resulting to a smaller distance between the waves which will show greater number of wavelengths between waves.</span>
5 0
3 years ago
A river flows down towards a lake along an incline. initially the river is 90 m above the lake flowing at a rate of 3 m/s. at th
lubasha [3.4K]

Total energy =kinetic energy +potential energy

Change in energy =change in (kinetic energy +potential energy)

potential energy, P.E=mgh

where m is the mass, g is acceleration due to gravity and h is the height.

potential energy per unit mass =gh

change in potential energy per unit mass = \Delta P.E.=g\Delta h

where, h is the height.

kinetic energy= K.E. =\frac{1}{2}mv^2

change in kinetic energy per unit mass,\Delta K.E. =\frac{1}{2}\Delta v^2

In the given question:

Height varies from 90 m to zero as river flows from 90 m height to lake at 0 m

Velocity varies from 3m/s at top to o m/s at bottom.

Therefore,

\Delta E =\Delta K.E.+\Delta P.E.\\ \Rightarrow \Delta E/m=\frac{1}{2}\Delta v^2+g\Delta h=\frac{1}{2}(0^2-3^2) m^2s^{-2}+9.8 (0-9)m^2s^{-2}=(-\frac{9}{2}-88.2)m^2s^{-2}=-92.7 m^2s^{-2}

Here, it was mentioned in the question internal energy of the water is constant and there is no change in the pressure at the inlet and outlet.

4 0
3 years ago
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