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3 years ago

If you add more molecules but do not change the temperature or the pressure, what will happen to the system?

Chemistry

1 answer:

VladimirAG [237]3 years ago

6 0

Answer:

the volume will increase

Explanation:

The kinetic energy of gas molecules depend upon the temperature . If temperature is increased , the molecules will move faster . When temperature is decreased , they move slower .

Hence when more molecules are added to a gas without changing its temperature , the velocity of gas molecules will remain unchanged .

Since pressure is also constant , it is volume which will be increased .

It can be explained from universal gas formula as follows

PV = nRT

P , R and T is constant ,

V ∝ n

Volume is proportional to n which depends upon number of molecules .

So volume will increase if number of molecules increases .

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If a object has a mass of 10 kilograms, how much does it weigh in newtons?

Len [333]

Depends on where the object is. On earth, moon , or somewhere without any other mass (theoretically). I think you mean how much does weigh on earth. So, the average gravitational acceleration on earth is : 9.83 m/s^2 To find out how much an object weighs, this is the formula : G=m.g where m is mass of the object g is the gravitational acceleration and G is weight. So, G = 10.9,83 = 98,3 N is the answer.

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3 years ago

What is the net ionic equation of the reaction of mgcl2 with naoh?

AveGali [126]

Answer:

The net ionic equation will be MgCl₂ + 2 NaOH → Mg(OH)₂ + 2 NaCl

Explanation:

Ionization of MgCl₂ is as follows

MgCl₂ → Mg²⁺ + 2 Cl⁻

Ionization of NaOH is as follows

NaOH → Na⁺ + OH⁻

It is a one type of substitution reaction where OH⁻ combined with Mg²⁺ to give magnesium hydroxide .

On the other hand Cl⁻ combined with Na⁺ to give sodium chloride as product.

Using proper stoichiometry to balanced the number of atoms in both side .

7 0

3 years ago

According to the activity series, which one of the following reactions will occur?

Korvikt [17]

Answer:

i think

SrF2 + Br2 --->

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Explanation:

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3 0

3 years ago

Determine the pH of the resulting solution if 25 mL of 0.400 M strychnine (C21H22N2O2) is added to 50 mL of 0.200 M HCl? Assume

DIA [1.3K]

Answer:

pH = 4.56

Explanation:

The strychnine reacts with HCl as follows:

C₂₁H₂₂N₂O₂ + HCl ⇄ C₂₁H₂₂N₂O₂H⁺ + Cl⁻

For strychnine buffer:

pOH = 5.74 + log [C₂₁H₂₂N₂O₂H⁺] / [C₂₁H₂₂N₂O₂]

Initial moles of C₂₁H₂₂N₂O₂ are:

0.025L * (0.400 mol / L) = 0.01 moles C₂₁H₂₂N₂O₂

And of HCl are:

0.05L * (0.200 mol / L) = 0.01 moles HCl

That means after the reaction, you will have just 0.01 moles of C₂₁H₂₂N₂O₂H⁺ in 50mL + 25mL = 0.075L. And molarity is:

[C₂₁H₂₂N₂O₂H⁺] = 0.01 mol / 0.075L = 0.1333M

This conjugate acid, is in equilibrium with water as follows:

C₂₁H₂₂N₂O₂H⁺(aq) + H₂O(l) ⇄ C₂₁H₂₂N₂O₂ + H₃O⁺

Where Ka = Kw / Kb = 1x10⁻¹⁴ / 1.8x10⁻⁶ = 5.556x10⁻⁹

Ka is defined as:

Ka = 5.556x10⁻⁹ = [C₂₁H₂₂N₂O₂] [H₃O⁺] / [C₂₁H₂₂N₂O₂H⁺]

In equilibrium, concentrations are:

C₂₁H₂₂N₂O₂ = X

H₃O⁺ = X

C₂₁H₂₂N₂O₂H⁺ = 0.1333M - X

Replacing in Ka expression:

5.556x10⁻⁹ = [X] [X] / [0.1333M - X]

7.39x10⁻¹⁰ - 5.556x10⁻⁹X = X²

7.39x10⁻¹⁰ - 5.556x10⁻⁹X - X² = 0

Solving for X:

X = - 2.72x10⁻⁵M → False solution. There is no negative concentrations

X = 2.72x10⁻⁵M → Right solution.

As H₃O⁺ = X

H₃O⁺ = 2.72x10⁻⁵M

And pH = -log H₃O⁺

4 0

3 years ago

How reliable is the perfect gas law in comparison with the van der waals equation?calculate the difference in pressure of 10.00g

Semmy [17]

Answer:

The perfect gas law is reliable at the limit of pressure tending to zero. That is to say, at low pressure. The Van der Waals law instead can be used at higher pressures.

Explanation:

The perfect law equation is

$P.V = n.R.T$

The perfect gas law considers that the gas molecules have no interaction between each other and each molecule has null volume. This condition happens at the limit of pressure tending to zero.

The Van der Waals equation is

$(P +\frac{n^{2}.a}{V^{2}})(V-n.b) = n.R.T$

On the other hand, the Van der Waals law has two extra terms, one to consider the interaction of the molecules (n2a/V2) and other to consider the volume of the molecules (V-nb). These terms make a better approximation to a real gas.

Using the two equations to calculate the pressure (P) for CO2 with

V = 100cm3 = 0.1L

T = 25ºC = 298K

n = 10g/(44g/mol) = 0.23mol

a = 3.658 atm.L2/mol2

b = 0.0429 L/mol

With the perfect law equation:

$P = \frac{n.R.T}{V} = \frac{0.23molx0.082\frac{atm.L}{K.mol}x298K }{0.1L} = 56.2atm$

With the Van del Waals law:

$P = \frac{n.R.T}{V-n.b} -\frac{n^{2}.a}{V^{2} }$

$P = \frac{0.23molx0.082\frac{atm.L}{K.mol}x298K}{0.1L - 0.23molx0.0429\frac{L}{mol} }-\frac{(0.23mol)^{2}x3.658\frac{atm.L^{2}}{mol^{2}}}{(0.1L)^{2}} = 43 atm$

At this case the difference between the results of the two equations is due to the big mass of CO2 which produce a high pressure.

8 0

3 years ago