coulomb's law
f repulsive = q1q2/4 pi epsilon nought r squared
0.1= q1q2/4 pi epsilon nought 0.911 squared
q1+q2= 7.50 µC
0.1= q1(7.5µC-q1)/4 pi epsilon nought 0.911 squared
solve for q1
Maybe show a picture ? I don’t get the question .
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Answer:</h2>
He saves 13.2 minutes
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Explanation:</h2>
Hey! The question is incomplete, but it can be found on the internet. The question is:
How many minutes did he save?
Let's call:

We know that the 135 miles are on the interstate highway where the speed limit is 65 mph. From this, we can calculate the time it takes to drive on this highway. Assuming Richard maintains constant the speed:

Today he is running late and decides to take his chances by driving at 73 mph, so the new time it takes to take the trip is:

So he saves the time
:

In minutes:

Answer:
Knowing we only have one load applied in just one direction we have to use the Hooke's law for one dimension
ex = бx/E
бx = Fx/A = Fx/π
Using both equation and solving for the modulus of elasticity E
E = бx/ex = Fx / π
ex
E = 
Apply the Hooke's law for either y or z direction (circle will change in every direction) we can find the change in radius
ey =
(бy - v (бx + бz)) =
бx
=
= 
Finally
ey = Δr / r
Δr = ey * r = 10 * 
Δd = 2Δr = 
Explanation: