Answer:
(6) Is proportional to L and inversely proportional to A.
Explanation:
I will explain it mathematically, following formula relates Resistance to length of wire L and cross sectional area A.
here, p is greek letter 'Rho' is called resistivity of the wire and L is lenght and A is cross sectional area of the wire.
By inspection we can tell that as length increases the resistance of wire increase, so resistance must be directly propoetional to length.
and resistance decrease as cross sectional area A decreases.
So the resistance must be directly proportional to Length of wire and inversly proportional to cross sectional area of wire.
option number (6) fits all of our deductions.
For every action<span>, </span>there<span> is </span>an<span> equal and </span>opposite reaction<span>.</span>
Answer:
a) E = 8628.23 N/C
b) E = 7489.785 N/C
Explanation:
a) Given
R = 5.00 cm = 0.05 m
Q = 3.00 nC = 3*10⁻⁹ C
ε₀ = 8.854*10⁻¹² C²/(N*m²)
r = 4.00 cm = 0.04 m
We can apply the equation
E = Qenc/(ε₀*A) (i)
where
Qenc = (Vr/V)*Q
If Vr = (4/3)*π*r³ and V = (4/3)*π*R³
Vr/V = ((4/3)*π*r³)/((4/3)*π*R³) = r³/R³
then
Qenc = (r³/R³)*Q = ((0.04 m)³/(0.05 m)³)*3*10⁻⁹ C = 1.536*10⁻⁹ C
We get A as follows
A = 4*π*r² = 4*π*(0.04 m)² = 0.02 m²
Using the equation (i)
E = (1.536*10⁻⁹ C)/(8.854*10⁻¹² C²/(N*m²)*0.02 m²)
E = 8628.23 N/C
b) We apply the equation
E = Q/(ε₀*A) (ii)
where
r = 0.06 m
A = 4*π*r² = 4*π*(0.06 m)² = 0.045 m²
Using the equation (ii)
E = (3*10⁻⁹ C)/(8.854*10⁻¹² C²/(N*m²)*0.045 m²)
E = 7489.785 N/C
<span>5.3 m/s
-------------------------------
</span>
Explanation:
One meter is equal to 
, so:
This wavelength does not correspond to any color of the visible spectrum. A wavelength of 
would correspond to soft X-rays, since these electromagnetic radiation have a wavelegth range from 
to 
.
