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brilliants [131]

2 years ago

15

When two objects collide is the momentum before equal to the momentum after the collision? What happens to the individual carts

momentum in terms of momentum before and after collision?

1 answer:

Alex787 [66]2 years ago

7 0

Answer:

a collision occuring between two objects in an isolated system, the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2.

thank you.

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A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to

dybincka [34]

Answer:

(A) Velocity of car in order just to clear the river and land safely on the opposite side is $29.68 \frac{m}{s}$

(B) The speed of the car is $35.14 \frac{m}{s}$

Explanation:

Given:

Car distance from river $y = 20.5$ m

Mere distance from river $y_{o} = 2.4$ m

River length $x= 57$ m

(A)

For finding the velocity of car,

Using kinematics equation we find velocity of car

$y - y_{o} = v_{o}t + \frac{1}{2} gt^{2}$

Where $v_{o} = 0$ , $g = 9.8$ $\frac{m}{s^{2} }$ ( given in question )

$20.5 - 2.4 = \frac{1}{2} \times 9.8 \times t^{2}$

$t= 1.92$ sec

The speed of the car before it lands safely on the opposite side of the river is given by,

$v_{x} = \frac{x-x_{o} }{t}$

$v_{x} = \frac{57-0}{1.92}$ ( $x_{o} = 0$ )

$v_{x} = 29.68$ $\frac{m}{s}$

(B)

For finding the speed,

The horizontal distance travel by car,

$v_{y} = v_{o} + at$

Where $a = 9.8$ $\frac{m}{s^{2} }$

$v_{y} = 9.8 \times 1.92$

$v_{y} = 18.81$ $\frac{m}{s}$

For finding the speed,

$v = \sqrt{v_{x}^{2} + v_{y} ^{2} }$

$v = \sqrt{(29.68)^{2}+ (18.81)^{2} }$

$v = 35.14$ $\frac{m}{s}$

Therefore, the speed of the car is $35.14 \frac{m}{s}$

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3 years ago

A banana has a mass of 1.4 kg. What is its weight, in Newtons?

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Answer

given :

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r/q = N

N = m(9.8)

= 1.4 kg(9.8)

= 13.72 Newton

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3 years ago

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If the frog lands with a velocity equal to its average velocity and comes to a full stop 0.25s later, what is the frog’s average

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Answer:

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$a=\frac{V-V0}{t}$

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