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Trava [24]
3 years ago
13

3. What is the difference between Synthetic Oil, Semi-Syntheic oil (Blend), High milage motor oil, and conventional motor oil? ​

Physics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

When evaluating synthetic blends, it's helpful to define the terms “synthetic blend” and “semi-synthetic”. Generally speaking, synthetic blends and semi-synthetic refer to the same thing: an oil that uses a combination of conventional and synthetic base oils in its formulation.

Explanation:

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Calculate the electric field strength at a point at which a test charge of 0.30 coulombs experiences a force of 5.0 newtons.
SVEN [57.7K]

The strength of electric field E is 17 N / C.

<u />

<u>Explanation:</u>

Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by

                     E = F / q

where E represents the electric field strength,

           F represents the force in newton,

           q represents the charge in coulomb.

Given the charge q = 0.30 coulombs

                   force F = 5.0 N

Electric field strength E = force / charge

                                        = 5.0 / 0.30

                                    E  = 16.66 = 17 N / C.

5 0
3 years ago
Can you please answers these for me please today is the last day to turn in work and I need this to pass please I’m begging than
Ymorist [56]

Answer:

1.   <u>F = ma</u>  <em>F = 0.2kg * 20m/s² = 4Kg * m/s² =</em> 4N

2.  <u>F = ma</u>  <em>F - 18Kg * 3m/s² = 54Kg * m/s² =</em> 54N

3.  <u>F = ma</u>  <em>F = 0.025Kg * 5m/s² =</em> 0.125N

4.  <u>F = ma</u>  <em>F = 50Kg * 4m/s² =</em> 200N

5.  <u>F = ma</u>  <em>F = 70Kg * 4m/s² =</em> 280N

6.  <u>F = ma</u>  <em>F = 9Kg * 9.8m/s² =</em> 88.2N

Explanation:

Hope this helps ! ^^

8 0
2 years ago
I NEED a LOT of help PLEASE!
Minchanka [31]
Infrared, visible light, then ultraviolet. Infrared is light that the human eye can not see and visible light is clearly light we can see then ultraviolet is has such a high frequency we can't see it either.
3 0
3 years ago
Read 2 more answers
A large, cylindrical water tank with diameter 3.60 m is on a platform 2.00 m above the ground. The vertical tank is open to the
zysi [14]

To solve this problem it is necessary to apply the concepts related to the geometry of a cylindrical tank and its respective definition.

The volume of a tank is given by

V = \frac{\pi d^2}{4}h

Where

d = Diameter

h = Height

Considering that there are two stages, let's define the initial and final volume as,

V_0 = \frac{\pi d^2}{4}H

V_f = \frac{\pi d^2}{4}h

We know as well by definition that

1gal = 3.785*10^{-3}m^3

Then we have for the statement that

V_f = V_0 -1gal

V_f = V_0 - 3.785*10^{-3}

Replacing the previous data

\frac{\pi d^2}{4}h = \frac{\pi d^2}{4}H- 3.785*10^{-3}

\frac{\pi (3.6)^2}{4}h = \frac{\pi (3.6)^2}{4}(2)- 3.785*10^{-3}

Solving to get h,

h = 1.99963m

Therefore the change is

\Delta h = H-h

\Delta h = 2- 1.99963

\Delta h = 3.7*10^{-4}m=0.37mm

Therefore te change in the height of the water in the tank is 0.37mm

4 0
3 years ago
3. Neha travels 4 m towards the north, 3m towards the east, and then 7 m towards south, find the displacement and total distance
Digiron [165]

Answer:

Explanation:

Explanation: total displacement =3√2m. and total distance covered=14m. I hope this is right and helps u.

7 0
3 years ago
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