A square rod is 2 m long and 0.5 m by 0.5 m in cross section. It elongates by 0.5 mm when subject to a tensile load P. The norma
1 answer:
Answer: the normal longitudinal strain is most nearly 2.5 x 10⁻⁴ mm/mm
Explanation:
Given the data in the question,
we know that;
Normal longitudinal strain = elongation / original length
so we substitute our values
Normal longitudinal strain = 0.5 mm / (2 m x 1000) mm
= 0.5 mm / 2000 mm
= 2.5 x 10⁻⁴ mm/mm
Therefore the normal longitudinal strain is most nearly 2.5 x 10⁻⁴ mm/mm
You might be interested in
Answer:
a)Δs = 834 mm
b)V=1122 mm/s
Explanation:
Given that
a)
When t= 2 s
s= 114 mm
At t= 4 s
s= 948 mm
So the displacement between 2 s to 4 s
Δs = 948 - 114 mm
Δs = 834 mm
b)
We know that velocity V
At t= 5 s
V=1122 mm/s
We know that acceleration a
a= 90 t
a = 90 x 5