All categories

3 years ago

What changes the boiling point of different alkanes?

Chemistry

1 answer:

mote1985 [20]3 years ago

3 0

Answer:

Therefore, the boiling points of the alkanes increase with molecular size. For isomers, the more branched the chain, the lower the boiling point tends to be. Van der Waals dispersion forces are smaller for shorter molecules and only operate over very short distances between one molecule and its neighbors.

The boiling points of the normal alkanes increase with increasing molecular weight (Table 3.3). As the molecular weight increases, London forces increase because more atoms are present to increase the surface area or the molecules.

HOPE IT HELPS

PLEASE GIVE ME BRAINLIEST THANK YOU!♥︎

You might be interested in

Please help very urgent! <3

LuckyWell [14K]

Answer:

a) Neutralisation

b) Combustion

c) Synthesis

d) Decomposition

e) Neutralisation

f) Double Displacement Reaction

h) Single Displacement Reaction

i) Double Displacement Reaction

j) Combustion

Explanation:

Synthesis is a reaction where various compounds/ elements react to form a totally new compound.

Decomposition is a reaction where a single compound breaks down into several components due to excessive heating or energy applied.

Single Displacement Reaction is a type of chemical reaction where an element reacts with a compound and takes the place of another element in that compound.

Double Displacement Reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

Combustion is a reaction where a compound/ element oxidises in the presence of Oxygen.

Neutralisation reaction is a reaction where an acid reacts with a base to form a salt.

5 0

3 years ago

10.0 grams of water are heated during the preparation of a cup of coffee 1.0x 103 j of the heat are added to the water. which is

katovenus [111]

Answer: The final temperature of the coffee is 43.9°C

Explanation:

To calculate the final temperature, we use the equation:

$q=mC(T_2-T_1)$

where,

q = heat released = $1.0\times 10^3J=1000J$

m = mass of water = 10.0 grams

C = specific heat capacity of water = 4.184 J/g°C

$T_2$ = final temperature = ?

$T_1$ = initial temperature = 20°C

Putting values in above equation, we get:

$1000J=10.0g\times 4.184J/g^oC\times (T_2-20)\\\\T_2=43.9^oC$

Hence, the final temperature of the coffee is 43.9°C

6 0

3 years ago

The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?

anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

$K_a\times K_b=K_w$

$K_b$ for sodium formate is $K_b=\frac {K_w}{K_a}$

Given that:

$K_a$ of formic acid = $1.8\times 10^{-4}$

And, $K_w=10^{-14}$

So,

$K_b=\frac {10^{-14}}{1.8\times 10^{-4}}$

$K_b=5.5556\times 10^{-11}$

Concentration = 0.35 M

HCOONa ⇒ Na⁺ + HCOO⁻

Consider the ICE take for the formate ion as:

HCOO⁻ + H₂O ⇄ HCOOH + OH⁻

At t=0 0.35 - -

At t =equilibrium (0.35-x) x x

The expression for dissociation constant of sodium formate is:

$K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}$

$5.5556\times 10^{-11}=\frac {x^2}{0.35-x}$

Solving for x, we get:

x = 0.44×10⁻⁵ M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

pH = 14 - 4.64 = 9.36

5 0

3 years ago

Sometimes you are given a measured amount of two or more reactants and asked how much product can be formed. Explain what steps

Westkost [7]

Explanation:

To solve this problem, follow these steps;

Obtain a balanced equation of the reaction and familiarize with the reactants and products.
Find the number of moles of the reacting species since they are the known matter in terms of quantity.
From the number of moles, determine the limiting reactant.
The limiting reactant is the one given in short supply.
Such reactant determines the extent of the reaction.
Compare the moles of this specie to that of the products using the balanced equation.
Obtain the mole of the desired product and find the mass or desired quantity.
simply work from the known specie to the unknown

learn more:

Number of moles brainly.com/question/13064292

#learnwithBrainly

4 0

3 years ago

What is the mass of 2.90 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?

ivann1987 [24]

40.0 g ( 1 mole ) --------------- 6.02x10²³ molecules
? ? --------------------------- 2.90x10²² molecules

mass = 2.90x10²² * 40.0 / 6.02x10²³

mass = 1.16x10²⁴ / 6.02x10²³

mass = 1.9269 g

hope this helps!

3 0

3 years ago