Answer:
d) osmotic pressure equal to that of blood
Explanation:
Answer is not a) because pH is concentration of positive hydrogen in solution but it not note all solutes. Answer is not b) because like answer a), it not note solutes without charge and, additionally it not note the pressure equilibrium when solvent flows through a membrane . Answer is not c) because it can be more or less water (solvent).
Answer:
0.127 N/m² or 0.127 Pa
Explanation:
From the question given above, the following data were obtained:
Radius (r) = 5 m
Force (F) = 40 N
Pressure (P) =.?
Next, we shall determine the Surface area of the sphere (i.e the balloon). This can be obtained as follow:
Surface area = 12.56 × r²
Radius (r) = 5 m
Surface area = 12.56 × 5²
Surface area = 12.56 × 25
Surface area = 314 m²
Finally, we shall determine the pressure as follow:
Force (F) = 40 N
Surface area = 314 m²
Pressure (P) =.?
Pressure = Force /Area
Pressure = 40/314
Pressure = 0.127 N/m² = 0.127 Pa
Therefore, the pressure inside the balloon is 0.127 N/m² or 0.127 Pa.
Answer:
The rate at which sulfur dioxide is being produced is 0.90 kg/s.
Explanation:
Volume of oxygen gas consumed in second ,V= 994 L
Pressure of the gas = p
Temperature of the gas = T = 170°C= 170 + 273 K=443 K
Moles of oxygen gas consumed in a second = n
( ideapl gas equation)

n = 21.044 mole
Moles of dioxygen gas consumed per second = 21.044 mol
(Claus process)
According to reaction, 3 moles of dioxygen gives 2 moles of sulfur dioxide gas.Then 21.044 moles of dioxygen will give;
of sulfur dioxide
Mass of 14.029 moles of sulfur dioxide gas;
14.029 mol × 64 g/mol = 897.86 g
897.86 g = 0.89786 kg ≈ 0.90 kg
Mass of sulfur dioxide produced per second = 0.90 kg
The rate at which sulfur dioxide is being produced is 0.90 kg/s.
The percent yield is 71.3 %.
Explanation:
Percent yield is the measure to analyze the success percentage of any experiment .The percent yield of any experiment can be obtained by the ratio of actual or experimental value to expected or theoretical value multiplied with 100.

So, in the present problem, we have obtained 10.7 g of adamantium nitrate from Wolverine's 10 pound claws. So the actual value or the experimental value is the amount of adamantium nitrate obtained from Wolverine's claws.
Thus, the experimental outcome is 10.7 g. While we had expected to recover 15 g of adamantium nitrate. So the theoretical outcome is 15 g.

Thus, the percent yield is 71.3 %.