Answer:
Buoyant Force: Cause and Calculation
The result is a net upward force (a buoyant force) on any object in any fluid. If the buoyant force is greater than the object's weight, the object will rise to the surface and float. If the buoyant force is less than the object's weight, the object will sink.
The object will move in the direction of the applied force.
Use a wedge, I would say. It would depend on the answers.
<span>The box is pushed initially.
F = ma;
m - mass of box
a - acceleration.
</span><span>
ma = -mu_k mg
</span><span>a = -mu_k g
</span><span>
Equation of motion: v^2 = u^2 + 2as
</span><span>
The box comes to a rest, v = 0 m/s
</span><span>
Here, u = 2 m/s and a = -`mu_k g = - 0.1 xx 9.81 = - 0.981 m/s^2
</span><span>Thus, u^2 = -2as
</span><span>s = u^2/(-2a) = (2^2) / (-2 x -0.981) = 2.04 m.
</span><span>
So the box will move a distance of 2.04 m over the rough surface.</span>
