Answer:
-3
4 - 7 = -3.
-3 + 7 = 4.
They are in a fact family.
The answer is -3.
Hope it helps!
Answer:
least to greatest: {61, 61, 61, 178, 179}
Step-by-step explanation:
If the third-largest angle is 61°, the smallest three angles cannot be larger than 183°. Since the total of all angles must be 540°, and the total of the largest two cannot be greater than 179°×2 = 358°, the sum of the smallest three must be at least 540° -358° = 182°.
So, the possible sets of angles with the smallest 3 totaling 182° or 183° are (in degrees) ...
{60, 61, 61, 179, 179} . . . . two modes
(61, 61, 61, 178, 179} . . . . . one mode -- the set you're looking for
I think that it would be A
A nice riddle, mathematical riddle.
Assuming a turtle winning means the declared winner is the weaker one actually won over the stronger one. In this context, the turtle winner is the one who has a lesser number of favourable votes.
The given rules for the points are as follows:
1. Point for the first choice must be greater than or equal to that of the second choice.
2. All points must be positive whole numbers.
Let's suppose we have Henry against Tim.
Henry is favourite of the voters and is the leading candidate, according to popular polls.
Tim is an excellent manipulator, sly, and everybody knows this.
On polling day, the vote count came out as follows (in point counts)
Henry Tim
2 1
2 1
2 1
2 1
2 1
2 1
10 1 (Henry's own vote)
1 100 (Tim's own vote)
------------------
17 107 TOTAL POINTS
So Tim the turtle was declared winner of the race, and since everything was according to rule, even a recount of the votes did not change the results.
Be aware, voting by districts (instead of popular votes) also exhibits a similar problem.
Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
