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elena-s [515]
2 years ago
8

Use the following electron configuration given below to answer the following question.

Chemistry
1 answer:
NemiM [27]2 years ago
4 0

Answer:

mental

Explanation:

the element is vanadium, it is a Transition metal

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Choose the aqueous solution below with the lowest freezing point. These are all solutions of nonvolatile solutes and you should
Ymorist [56]

Answer:

B. 0.075 m (NH4)3PO4

Explanation:

Our strategy here is to recall the van´t Hoff factor, i, for the colligative properties of electrolyte solutions which appears as the consequence that electrolytes disociate completely in their solutions in water.

Thus in this problem we need to determine i and then realize the one with the lowest freezing point will have the biggest  i ( all the concentrations are equal) since

ΔTf = i m Kf

Substance  van´t Hoff factor

Li I                             2

(NH4)3PO4              4

NaIO4                       2

KCN                          2

KNO2                       2

The correct answer is B. 0.075 m (NH4)3PO4

4 0
3 years ago
Two 0.75 Amp loads are connected in parallel with a 2500 Milliamperehour Ni-Cd battery. Approximately how long can the battery p
nikdorinn [45]

Explanation:

It is given that two loads have 0.75 Ampere current each. And, they contain 2500 milli ampere per hour Ni-Cd battery.

As both the loads are connected in parallel. Hence, total current will be calculated as follows.

               I = I_{1} + I_{2}

                 = 0.75 A + 0.75 A

                 = 1.5 A

                 = 1.5 A \times \frac{1000 mA}{1 A}

                 = 1500 mA

Relation between time and capacity of battery is as follows.

             Capacity = Current × time (in hour)

therefore,        time = \frac{Capacity}{Current}

                                = \frac{2500 mA. h}{1500 A}

                                = 1.667 hr

Thus, we can conclude that the battery provide power to the load up to 1.667 hours.

4 0
3 years ago
A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th
mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene,          Solvent 2 = water

 K_{p} = 2.7,         V_{S_{2}} = 100 mL

V_{S_{1}} = 10 mL,       weight of compound = 1 g

       Extract = 3

Therefore, calculate the fraction remaining as follows.

                  f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}

                                  = [1 + 2.7(\frac{100}{10})]^{-3}

                                  = (28)^{-3}

                                  = 4.55 \times 10^{-5}

Hence, weight of compound to be extracted = weight of compound - fraction remaining

                                  = 1 - 4.55 \times 10^{-5}

                                  = 0.00001

or,                               = 1 \times 10^{-5}

Thus, we can conclude that weight of compound that could be extracted is 1 \times 10^{-5}.

7 0
3 years ago
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The volume is 3900cm^3 and the bricks density is 3900 ml
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A _______ is formed when tectonic plates collide.
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A convergent plate boundary is formed when tectonic plates collide
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