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adelina 88 [10]

3 years ago

10

A swimmer can inhale exactly 0.25 moles of air before diving underwater. What will be the total volume of the swimmer’s lungs at

0.97 atm and 17.6 0C?

1 answer:

Crank3 years ago

6 0

Answer:

6.14 L

Explanation:

To answer this question we'll<u> use the PV=nRT formula</u>, where:

P = 0.97 atm

V = ?

n = 0.25 mol

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 17.6 °C ⇒ 17.6 + 273.16 = 209.76 K

We <u>input the data</u>:

0.97 atm * V = 0.25 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 209.76 K

And <u>solve for V</u>:

V = 6.14 L

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