A)Cu2O(s) + C(s) ———> 2Cu(s)+ CO(g)
B)H2(g) +Cl2(g)———> 2HCl(g)
Equation is:
Ca(NO3)2 + Na3PO4 —> NaNO3 + Ca3(PO4)2
Balance it out
3Ca(NO3)2 + 2Na3PO4 —> 6NaNO3 + Ca3(PO4)2
You have 96.1g of Calcium Nitrate
Moles = Mass/Molar Mass
Molar mass of Calcium Nitrate is 164.088 g/mol
96.1g / 164.088 g/mol =0.586 moles
Mole ratio is 3:1
Therefore 0.586/3 moles of calcium phosphate
Moles x molar mass = mass
0.586/3 x 310.18 g/mol = 60.6~g roughly as theoretical yield
Ice is the solid phase of water, so it is not silicate.
Answer:
Volume of HNO₃ required = 140 mL
Explanation:
Given data:
Molarity of HNO₃ = 0.563 M
mass of BaCO₃ = 7.83 g
Volume of HNO₃ = ?
Solution:
First of all we will write the balance chemical equation
2HNO₃ + BaCO₃ → Ba(NO₃)₂ + H₂O + CO₂
Number of moles of BaCO₃ = mass / molar mass
Number of moles of BaCO₃ = 7.83 g / 197.34 g/mol
Number of moles of BaCO₃ = 0.04 mol
Now we compare the moles of BaCO₃ and HNO₃ .
BaCO₃ : HNO₃
1 : 2
0.04 : 2×0.04 = 0.08 mol
Volume of HNO₃ required = number of moles / Molarity
Volume of HNO₃ required = 0.08 mol / 0.563 mol/L
Volume of HNO₃ required = 0.14 L
0.14 × 1000 = 140 mL
Answer:
C3H8 + 5O2 ====> 3CO2 + 4H20
