Answer: -
0.1 ml of bleach should be added to each liter of test solution.
Explanation:-
Let the volume of bleach to be added is B ml.
Density of stock solution = 1.0 g/ml
Mass of stock solution = Volume of stock x density of stock
= B ml x 1.0 g/ml
= B g
Amount of NaOCl in this stock solution = 5% of B g
= 
x B g
= 0.05 B g
Now each test solution must be added 5 mg/l NaOCl.
Thus each liter of test solution must have 5 mg.
Thus 0.05 B g = 5 mg
= 0.005 g
B = 
= 0.1
Thus 0.1 ml of bleach should be added to each liter of test solution.
Answer:
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Explanation:
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Homeostasis is the ability to maintain stable internal conditions B is the answer
I thought the answer is d
Answer:
A reduction-oxidation (redox) reaction will occur.
Chlorine gas (Cl2) will accept electrons to form Cl- ions.
The Iron(II) ions (Fe2+) will lose electrons to form Fe3+ ions. (Iron (III) ions)
Fe2+ ions are green, while Fe3+ ions are yellow,
so the observation will be the solution turning from green to yellow.
