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Displacement-1



Displcaement-2


Total displacement=600+600=1200m
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).
If we call

the speed of the primary waves and

the speed of the secondary waves, and we call

the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as


So the lag time between the arrival of the P-waves and of the S-waves is

We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
Answer:
1.17 x 10^2 L
Explanation:
We can find the volume of the gas by using the ideal gas law:

where we have:
is the pressure
V is the volume
n = 4.8 mol is the number of moles
R = 0.0821 L · atm/mol · K is the ideal gas constant
is the temperature
Solving the equation for V, we find the volume

Answer:
45.89m/s²
Explanation:
Given
Distance S = 305m
Time t = 3.64s
To get the acceleration during this run, we will apply the equation of motion:
S = ut+1/2at²
Substitute the given parameters into the formula and calculate the value of a
305 = 0+1/2 a(3.64)²
304 = 1/2(13.2496)a
304 = 6.6248a
a = 304/6.6248
a = 45.89m/s²
Hence the average acceleration during this run is 45.89m/s²