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2 years ago

10

3. If nothing can ever be at absolute zero, why does the concept exist?

1 answer:

JulijaS [17]2 years ago

6 0

The reason has to do with the amount of work necessary to remove heat from a substance, which increases substantially the colder you try to go. To reach zero kelvins, you would require an infinite amount of work.

You might be interested in

What color is a board sternlight

alukav5142 [94]

We can infer and logically deduce that the color of a boat's sternlight is white.

<h3>What is a sternlight?</h3>

A sternlight can be defined as a white light that is designed and developed to be placed as closely as possible and practical with the stern shining continuously (constantly).

By default, a sternlight is typically affixed to the boat in such a way that the light will shine out at an angle of 135 degrees (135°) from the back of the boat.

In this context, we can infer and logically deduce that the color of a boat's sternlight is white and it avails sailors and other persons the opportunity of determining and knowing the direction that a boat (vessel) is moving.

Read more on sternlight here: brainly.com/question/27999695

#SPJ1

Complete Question:

What color is a boat sternlight?

3 0

2 years ago

Nitrogen (N2) contained in a piston–cylinder arrangement, initially at 10 bar and 405 K, undergoes an expansion to a final tempe

yKpoI14uk [10]

Answer:28.21 kJ/kg

Explanation:

Given

$P_1=10\ bar$

$T_1=405\ K$

$T_2=300\ K$

Process $PV^{1.3}=constant$

Work done for Polytropic process

$W=\dfrac{P_1V_1-P_2V_2}{n-1}$

where n=Polytropic index

$W=\dfrac{R(T_1-T_2)}{n-1}$

$W=\dfrac{0.296(405-300)}{1.3-1}\quad [R_{N_2}=\frac{8.314}{28}]$

$W=103.6\ kJ\kg$

Now Calculating change in Internal energy

$\Delta U=c_v(T_2-T_1)$

$\Delta U=0.718\times (300-405)$

$\Delta U=-75.39\ kJ/kg$

Now applying First law concept

$\Delta U=Q-W$

$Q=W+\Delta U$

$Q=103.6-75.392$

$Q=28.21\ kJ/kg$

6 0

4 years ago

A manufacturer makes two types of drinking straws: one with a square cross-sectional shape, and the other type the typical round

Harlamova29_29 [7]

Answer:

$\frac{Q_{square}}{Q_{circle}} = 0.785$

Explanation:

given data

types of drinking straws

square cross-sectional shape
round shape

solution

we know that both perimeter of the cross section are equal

so we can say that

perimeter of square = perimeter of circle

4 × S = π × D

here S is length and D is diameter

S = $\frac{\pi D}{4}$ ....................1

and

ratio of flow rate through the square and circle is here

$\frac{Q_{square}}{Q_{circle}} = \frac{AV^2}{AV^2}$

$\frac{Q_{square}}{Q_{circle}} = \frac{S^2}{\frac{\pi D^2}{4}}$

$\frac{Q_{square}}{Q_{circle}} = \frac{(\frac{\pi D}{4})^2}{\frac{\pi D^2}{4}}$

$\frac{Q_{square}}{Q_{circle}} = \frac{\pi }{4}$

$\frac{Q_{square}}{Q_{circle}} = 0.785$

4 0

4 years ago

Which kind of fracture (ductile or brittle) is associated with each of the two crack propagation mechanisms?

Nina [5.8K]

dutile is the correct answer

6 0

3 years ago

Overview In C, a string is simply an array of characters. We have used literal strings all along – the stuff in between the quot

salantis [7]

#include<stdio.h>

#include<string.h>

int main() {

char str1[100];

char str2[100];

printf("\nEnter the String 1 : ");

gets(str1);

strcpy(str2, str1);

printf("\nCopied String : %s", str2);

return (0);

}

3 0

3 years ago