<span> In this question (t½) of C-14 is 5730 years, which means that after 5730 years half of the sample would have decayed and half would be left as it is. After 5730 years ( first half life) 70 /2 = 35 mg decays and 35 g remains left. After another 5730 years ( two half lives or 11460 years) 35 /2 = 17.5mg decays and ...</span>Missing: <span>25g</span>
Answer:
Explanation:
The coefficient of the kth term (ordering in increasing order for the exponent of x) is just the number of ways we have to choose k factors from that expression, so if we let k be the exponent of x, and n be the total number of terms, the coefficient of x^k is
Which, of course, we have to multiply for the product of the two terms.
For example, the coefficient of the third grade term in is
So we have
Which is equal to
Hope this helps :)
Answer:
See explanation and images attached
Explanation:
There are two compounds that could have molecular formula of C2H6O, they are ethanol and methoxy methane (trivial name: methyl ether). The structures of the two compounds are shown in the image attached as obtained from quora.
The boiling point of methoxymethane is -24.8°C while that of ethanol is about 78.5°C. The reason for the high boiling point of ethanol is the presence of intermolecular hydrogen bonding leading to a stronger intermolecular interaction compared to methoxymethane molecules held together only by very weak dispersion forces.
I'm pretty sure it's the law of conservation of matter