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sattari [20]
3 years ago
7

35 cm3 of a metal has a mass of 121 grams. whats is its density?

Chemistry
1 answer:
dusya [7]3 years ago
5 0

Answer:

The density of the metal is 3.457 g/cm³.

Explanation:

Given,

mass of metal = 121 grams

Volume = 35 cm³.

Density = ?

Density of the metal can be found by using the formula

Density = Mass/Volume

Substituting the values,

Density = 121/35 = 3.457 g/cm³.

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<span>Heavier atoms make denser materials</span>
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What is the total number of valence electrons in the dot structure of CBr4? Explain how you determined this answer. What is the
Mnenie [13.5K]

Answer:- There are 32 valence electrons and it's tetrahedral in shape.

Explanations:- Atomic number of carbon is 6 and it's electron configuration is 1s^22s^22p^2 . It has 4 electrons in the outer most shell means it has 4 valence electrons.

Atomic number of Br is 35 and it's electron configuration is 1s^22s^22p^63s^23p^64s^23d^1^04p^5 . It has 7 electrons in the outer most shell(2 in 4s and 5 in 4p) .

There is one C and four Br in the given compound. So, total number of valence electrons = 4+4(7) = 4+28 = 32

Four Br atoms are bonded to the central carbon atom and also there isn't any lone pair present on carbon. It makes it tetrahedral.

5 0
3 years ago
Is melting sugar a chemical or physical change? Please provide an explanation
liraira [26]

Answer:

Hola Amigo! Here's Ur Answer :D

Explanation:

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3 0
3 years ago
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ASAP worth 15 points also
Taya2010 [7]
The person above me is correct I took a test on this so it’s the right answer
7 0
3 years ago
What is the theoretical yield of NaBr
dolphi86 [110]

The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles

<h3>Balanced equation </h3>

2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr

From the balanced equation above,

2 moles FeBr₃ reacted to produce 6 moles of NaBr

<h3>How to determine the theoretical yield of NaBr</h3>

From the balanced equation above,

2 moles FeBr₃ reacted to produce 6 moles of NaBr

Therefore,

2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr

Therefore,

Thus, the theoretical yield of NaBr is 7.08 moles

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

7 0
2 years ago
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