Answer:
P=atm
Explanation:
The problem give you the Van Der Waals equation:
First we are going to solve for P:
Then you should know all the units of each term of the equation, that is:
where atm=atmosphere, L=litters, K=kelvin
Now, you should replace the units in the equation for each value:
Then you should multiply and eliminate the same units which they are dividing each other (Please see the photo below), so you have:
Then operate the fraction subtraction:
P=
And finally you can find the answer:
P=atm
Now solving for b:
Replacing units:
Multiplying and dividing units,(please see the second photo below), we have:
→
Explanation:
- The products formed are chromic chloride and cobalt.
Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt
- Type of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.
Reactants used in the reaction are -
- Chromium
- Cobaltous Chloride
Products formed in the reaction are -
- Chromic Chloride
- Cobalt
Hence, the chemical reaction is as follows -
- →
For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.
Hence, the balanced equation is -
→
Answer:
The answer to your question is: 101.2 g of CO2
Explanation:
C = 27.6 g
O₂ = 86.5 g remained 12.9 g
O₂ that reacted = 86.5 - 12.9 = 73.6 g
C + O₂ ⇒ CO₂ The equation is balanced
27.6 73.6 ?
MW 12 32 44
Rule of three
12 g of C------------------ 44 g CO2
27.6 g C ------------------ x
x = 27.6(44)/12 = 101.2 g of CO2
32 g of O2 --------------- 44 g of CO2
73.6 g of O2 ------------ x
x = 73.6(44)/32 = 101.2 g of CO2
Answer:
Volume of carbon dioxide is 428.23 L.
Explanation:
Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.
Here, undecane is in liquid form that reacts with gaseous oxygen (combustion) and produces carbon dioxide and water as a product in the gaseous form.
The molar mass of undecane =
From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.
Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.