Answer:
Actors affecting the flight path of a Projectile are:
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When heat energy is supplied to a material it can raise the temperature of mass of the material.
Specific heat is the amount of energy required by 1 g of material to raise the temperature by 1 °C.
equation is
H = mcΔt
H - heat energy
m - mass of material
c - specific heat of the material
Δt - change in temperature
substituting the values in the equation
120 J = 10 g x c x 5 °C
c = 2.4 Jg⁻¹°C⁻¹
Answer:
The main purpose of the expedition was to conduct a hydrographic survey of the coasts of the southern part of South America.
Answer:1. ![Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=Rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. The rate constant (k) for the reaction is 
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![rate=k[CHCl_3]^x[Cl_2]^y](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5Ex%5BCl_2%5D%5Ey)
k= rate constant
x = order with respect to 
y = order with respect to 
n = x+y= Total order
1. a) From trial 1: ![0.0035=k[0.010]^x[0.010]^y](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5Ex%5B0.010%5D%5Ey)
(1)
From trial 2: ![0.0069=k[0.020]^x[0.010]^y](https://tex.z-dn.net/?f=0.0069%3Dk%5B0.020%5D%5Ex%5B0.010%5D%5Ey)
(2)
Dividing 2 by 1 :![\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0069%7D%7B0.035%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D%7Bk%5B0.010%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore x=1.
b) From trial 2: (3)
From trial 3: ![0.0098=k[0.020]^x[0.020]^y](https://tex.z-dn.net/?f=0.0098%3Dk%5B0.020%5D%5Ex%5B0.020%5D%5Ey)
(4)
Dividing 4 by 3:![\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0098%7D%7B0.0069%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.020%5D%5Ey%7D%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore 
![rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. to find rate constant using trial 1:
![0.0035=k[0.010]^1[0.010]^\frac{1}{2}](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5E1%5B0.010%5D%5E%5Cfrac%7B1%7D%7B2%7D)
The question in English is "<span>Determine the mass, in kg, of a material that is contained in a volume of 18L. It is known that the material density is 0.9 g/cm 3"
Answer:
</span>
We can use a simple
equation to solve this problem. <span>
d =
m/v</span><span>
<span>Where </span>d <span>is
the density, </span>m <span>is
the mass and </span>v is the volume.
d = </span>0.9<span> g/cm³
m = ?
v = </span>18 L = 18 x 10³ cm³<span>
By applying the equation,
<span> 0.9 g/cm³ = m / </span></span>18 x 10³ cm³<span>
m = 0.9 g/cm³ x </span>18 x 10³ cm³<span>
<span>
</span>m = 16200 g
m = 16.2 kg
Hence, the mass of
18 L of material is 16.2 kg.</span>
