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maksim [4K]
3 years ago
13

pb(No3)2(aq) +2KCI(aq)---PbCl2(s)+KNO2(aq). how many grams of PbCl2 solution will react with a 0.46 L of a 0.101m KCI solution​

Chemistry
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

6.3986g

Explanation:

The balanced chemical equation of this reaction is as follows:

Pb(NO3)2(aq) + 2KCl (aq) → PbCl2(s) + 2KNO3(aq)

In this equation, 2 moles of KCl solution will produce 1 mole of PbCl2.

To calculate the number of moles of PbCl2 produced, we use the formula:

Molarity = number of moles (n) ÷ volume (V)

0.101 = n/0.46

n = 0.046mol of KCl

If 2 moles of KCl solution will produce 1 mole of PbCl2

Then, 0.046mol of KCl will be react to produce (0.046 × 1/2) of PbCl2

0.046 × 1/2 = 0.023mol of PbCl2

To find the mass of PbCl2 using mole = mass ÷ molar mass

Molar mass of PbCl2 = 207.2 + 35.5(2)

= 207.2 + 71

= 278.2g/mol

0.023 = mass/278.2

mass = 6.3986g

stiv31 [10]3 years ago
7 0

Answer:

Can you help me with other question please

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